Overview: 3 questions will be solved this time.Among them
           ☆3 equations

[ 1/3 Equation]
    Work: Find the solution of equation 6+5(2y-1) = (2y-1)^2 .
    Question type: Equation
    Solution:
    After the equation is converted into a general formula, it is converted into:
    ( y +0 )( 2y - 7 )=0
    From
        y + 0 = 0
        2y - 7 = 0
    it is concluded that:：
        y₁=0

y2=

7 2

    
    There are 2 solution(s).

解一元二次方程的详细方法请参阅：《一元二次方程的解法》
[ 2/3 Equation]
    Work: Find the solution of equation (2y+1)^2+3(2y+1)+2 = 0 .
    Question type: Equation
    Solution:
    After the equation is converted into a general formula, it is converted into:
    ( 2y + 3 )( y + 1 )=0
    From
        2y + 3 = 0
        y + 1 = 0
    it is concluded that:：

y1=

-

3 2

y2=-1

    
    There are 2 solution(s).

解一元二次方程的详细方法请参阅：《一元二次方程的解法》
[ 3/3 Equation]
    Work: Find the solution of equation 4(x-1)^2-9(3-2x)^2 = 0 .
    Question type: Equation
    Solution:
    After the equation is converted into a general formula, it is converted into:
    ( 8x - 11 )( 4x - 7 )=0
    From
        8x - 11 = 0
        4x - 7 = 0
    it is concluded that:：

x1=

11 8

x2=

7 4

    
    There are 2 solution(s).

解一元二次方程的详细方法请参阅：《一元二次方程的解法》

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