Mathematics
         
语言:中文    Language:English
                                Equations   
Fold
                                Unary equation
                                Multivariate equation
                                Math OP  
Unfold
                                Linear algebra      
Unfold
                                Derivative function
                                Function image
                                Hot issues
On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 4.0924 = (20.74389086(x+0.1))/(1+0.8666(x+0.1))*(100-1.21-21.62)/100*1/(1+0.31*1.21)+(4.11(x+0.1))/(1.4*0.101325) .
    Question type: Equation
    Solution:Original question:
     
10231
2500
= (
1037194543
50000000
( x +
1
10
)) ÷ (1 +
4333
5000
( x +
1
10
)) × (100
121
100
1081
50
) ÷ 100 × 1 ÷ (1 +
31
100
×
121
100
) + (
411
100
( x +
1
10
)) ÷ (
7
5
×
4053
40000
)
     Multiply both sides of the equation by:(1 +
4333
5000
( x +
1
10
))
     
10231
2500
(1 +
4333
5000
( x +
1
10
)) = (
1037194543
50000000
( x +
1
10
))(100
121
100
1081
50
) ÷ 100 × 1 ÷ (1 +
31
100
×
121
100
) + (
411
100
( x +
1
10
)) ÷ (
7
5
×
4053
40000
) × (1 +
4333
5000
( x +
1
10
))
    Remove a bracket on the left of the equation::
     
10231
2500
× 1 +
10231
2500
×
4333
5000
( x +
1
10
) = (
1037194543
50000000
( x +
1
10
))(100
121
100
1081
50
) ÷ 100 × 1 ÷ (1 +
31
100
×
121
100
) + (
411
100
( x +
1
10
)) ÷ (
7
5
×
4053
40000
) × (1 +
4333
5000
( x +
1
10
))
    Remove a bracket on the right of the equation::
     
10231
2500
× 1 +
10231
2500
×
4333
5000
( x +
1
10
) =
1037194543
50000000
( x +
1
10
)(100
121
100
1081
50
) ÷ 100 × 1 ÷ (1 +
31
100
×
121
100
) + (
411
100
( x +
1
10
)) ÷ (
7
5
×
4053
40000
) × (1 +
4333
5000
( x +
1
10
))
    The equation is reduced to :
     
10231
2500
+
44330923
12500000
( x +
1
10
) =
1037194543
5000000000
( x +
1
10
)(100
121
100
1081
50
) ÷ (1 +
31
100
×
121
100
) + (
411
100
( x +
1
10
)) ÷ (
7
5
×
4053
40000
) × (1 +
4333
5000
( x +
1
10
))
     Multiply both sides of the equation by:(1 +
31
100
×
121
100
)
     
10231
2500
(1 +
31
100
×
121
100
) +
44330923
12500000
( x +
1
10
)(1 +
31
100
×
121
100
) =
1037194543
5000000000
( x +
1
10
)(100
121
100
1081
50
) + (
411
100
( x +
1
10
)) ÷ (
7
5
×
4053
40000
) × (1 +
4333
5000
( x +
1
10
))(1 +
31
100
×
121
100
)
    Remove a bracket on the left of the equation:
     
10231
2500
× 1 +
10231
2500
×
31
100
×
121
100
+
44330923
12500000
( x +
1
10
)(1 +
31
100
×
121
100
) =
1037194543
5000000000
( x +
1
10
)(100
121
100
1081
50
) + (
411
100
( x +
1
10
)) ÷ (
7
5
×
4053
40000
) × (1 +
4333
5000
( x +
1
10
))(1 +
31
100
×
121
100
)
    Remove a bracket on the right of the equation::
     
10231
2500
× 1 +
10231
2500
×
31
100
×
121
100
+
44330923
12500000
( x +
1
10
)(1 +
31
100
×
121
100
) =
1037194543
5000000000
x (100
121
100
1081
50
) +
1037194543
5000000000
×
1
10
(100
121
100
1081
50
) + (
411
100
( x +
1
10
)) ÷ (
7
5
×
4053
40000
) × (1 +
4333
5000
( x +
1
10
))(1 +
31
100
×
121
100
)

    The solution of the equation:
        x1≈-1.253935 , keep 6 decimal places
        x2≈0.405553 , keep 6 decimal places
    
    There are 2 solution(s).


解程的详细方法请参阅:《方程的解法》



Your problem has not been solved here? Please go to the Hot Problems section!





  New addition:Lenders ToolBox module(Specific location:Math OP > Lenders ToolBox ),welcome。