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On line Solution of Monovariate Equation：
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation （0.4-0.05）x+(290-0.4x)/0.3*(0.3-0.05) = 250 .
    Question type: Equation
    Solution:Original question:
     (
2
5
 −
1
20
) x + (290 −
2
5
 x ) ÷
3
10
 × (
3
10
 −
1
20
) = 250
    Remove the bracket on the left of the equation:
     Left side of the equation =
2
5
 x −
1
20
 x + (290 −
2
5
 x ) ×
10
3
(
3
10
 −
1
20
)
                                             =
7
20
 x + (290 −
2
5
 x ) ×
10
3
(
3
10
 −
1
20
)
                                             =
7
20
 x + 290 ×
10
3
(
3
10
 −
1
20
) −
2
5
 x ×
10
3
(
3
10
 −
1
20
)
                                             =
7
20
 x +
2900
3
(
3
10
 −
1
20
) −
4
3
 x (
3
10
 −
1
20
)
                                             =
7
20
 x +
2900
3
 ×
3
10
 −
2900
3
 ×
1
20
 −
4
3
 x (
3
10
 −
1
20
)
                                             =
7
20
 x + 290 −
145
3
 −
4
3
 x (
3
10
 −
1
20
)
                                             =
7
20
 x +
725
3
 −
4
3
 x (
3
10
 −
1
20
)
                                             =
7
20
 x +
725
3
 −
4
3
 x ×
3
10
 +
4
3
 x ×
1
20
                                             =
7
20
 x +
725
3
 −
2
5
 x +
1
15
 x
                                             =
1
60
 x +
725
3
    The equation is transformed into :
     
1
60
 x +
725
3
 = 250

    Transposition :
     
1
60
 x = 250 −
725
3

    Combine the items on the right of the equation:
     
1
60
 x =
25
3

    The coefficient of the unknown number is reduced to 1 :
      x =
25
3
 ÷
1
60
        =
25
3
 × 60
        = 25 × 20

    We obtained :
      x = 500
    This is the solution of the equation.



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