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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation a(a+1)(a+2)-2(a+1)(a+2)(a+3) = 1 .
    Question type: Equation
    Solution:Original question:
      a ( a + 1)( a + 2)2( a + 1)( a + 2)( a + 3) = 1
    Remove the bracket on the left of the equation:
     Left side of the equation = a a ( a + 2) + a × 1( a + 2)2( a + 1)( a + 2)( a + 3)
                                             = a a a + a a × 2 + a × 1( a + 2)2( a + 1)( a + 2)
                                             = a a a + a a × 2 + a × 1 a + a × 1 × 2
                                             = a a a + a a × 2 + a × 1 a + a × 22
                                             = a a a + a a × 2 + a × 1 a + 2 a 2
                                             = a a a + a a × 2 + a × 1 a + 2 a 2
                                             = a a a + a a × 2 + a × 1 a + 2 a 2
                                             = a a a + a a × 2 + a × 1 a + 2 a 2
                                             = a a a + a a × 2 + a × 1 a + 2 a 2
                                             = a a a + a a × 2 + a × 1 a + 2 a 2
                                             = a a a + a a × 2 + a × 1 a + 2 a 2
                                             = a a a + a a × 2 + a × 1 a + 2 a 2
                                             = a a a + a a × 2 + a × 1 a 10 a 2
                                             = a a a + a a × 2 + a × 1 a 10 a 2
                                             = a a a + a a × 2 + a × 1 a 10 a 2
                                             = a a a + a a × 2 + a × 1 a 10 a 2
                                             = a a a + a a × 2 + a × 1 a 10 a 2
                                             = a a a + a a × 2 + a × 1 a 16 a 2
                                             = a a a + a a × 2 + a × 1 a 16 a 2
                                             = a a a + a a × 2 + a × 1 a 16 a 2
                                             = a a a + a a × 2 + a × 1 a 20 a 2
    The equation is transformed into :
      a a a + a a × 2 + a × 1 a 20 a 2 = 1

    The solution of the equation:
        a1≈-6.048917 , keep 6 decimal places
        a2≈-1.643104 , keep 6 decimal places
        a3≈-1.307979 , keep 6 decimal places
    
    There are 3 solution(s).


解程的详细方法请参阅:《方程的解法》



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