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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 25220-(25220/1.13*0.13-x/1.13*0.13)*1.12-(25220/1.13+x/1.13)*0.0003-(25220/1.13-x/1.13)*0.05-3000 = x .
    Question type: Equation
    Solution:Original question:
     25220(25220 ÷
113
100
×
13
100
x ÷
113
100
×
13
100
) ×
28
25
(25220 ÷
113
100
+ x ÷
113
100
) ×
3
10000
(25220 ÷
113
100
x ÷
113
100
) ×
1
20
3000 = x
     Left side of the equation = 22220(25220 ÷
113
100
×
13
100
x ÷
113
100
×
13
100
) ×
28
25
(25220 ÷
113
100
+ x ÷
113
100
) ×
3
10000
(25220 ÷
113
100
x ÷
113
100
) ×
1
20
    The equation is transformed into :
     22220(25220 ÷
113
100
×
13
100
x ÷
113
100
×
13
100
) ×
28
25
(25220 ÷
113
100
+ x ÷
113
100
) ×
3
10000
(25220 ÷
113
100
x ÷
113
100
) ×
1
20
= x
    Remove the bracket on the left of the equation:
     Left side of the equation = 2222025220 ÷
113
100
×
13
100
×
28
25
+ x ÷
113
100
×
13
100
×
28
25
(25220 ÷
113
100
+ x ÷
113
100
) ×
3
10000
(25220 ÷
113
100
x ÷
113
100
)
                                             = 22220
1836016
565
+ x ×
364
2825
(25220 ÷
113
100
+ x ÷
113
100
) ×
3
10000
(25220 ÷
113
100
x ÷
113
100
) ×
1
20
                                             =
10718284
565
+
364
2825
x (25220 ÷
113
100
+ x ÷
113
100
) ×
3
10000
(25220 ÷
113
100
x ÷
113
100
) ×
1
20
                                             =
10718284
565
+
364
2825
x 25220 ÷
113
100
×
3
10000
x ÷
113
100
×
3
10000
(25220 ÷
113
100
x ÷
113
100
) ×
1
20
                                             =
10718284
565
+
364
2825
x
3783
565
x ×
3
11300
(25220 ÷
113
100
x ÷
113
100
) ×
1
20
                                             =
10714501
565
+
1453
11300
x (25220 ÷
113
100
x ÷
113
100
) ×
1
20
                                             =
10714501
565
+
1453
11300
x 25220 ÷
113
100
×
1
20
+ x ÷
113
100
×
1
20
                                             =
10714501
565
+
1453
11300
x
126100
113
+ x ×
5
113
                                             =
10084001
565
+
1953
11300
x
    The equation is transformed into :
     
10084001
565
+
1953
11300
x = x

    Transposition :
     
1953
11300
x x = -
10084001
565

    Combine the items on the left of the equation:
     
9347
11300
x = -
10084001
565

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
     
10084001
565
=
9347
11300
x

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
     
9347
11300
x =
10084001
565

    The coefficient of the unknown number is reduced to 1 :
      x =
10084001
565
÷
9347
11300
        =
10084001
565
×
11300
9347
        =
10084001
113
×
2260
9347

    We obtained :
      x =
22789842260
1056211
    This is the solution of the equation.



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