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On line Solution of Monovariate Equation：
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 1460.50+1460.50*0.03+0.03X+(1460.50+1460.50*0.03+0.03X)*0.0475*2/2+(1460.50+1460.50*0.03+0.03X+(1460.50+1460.50*0.03+0.03X)*0.0475*2/2)*0.3+0.0524X = 0 .
    Question type: Equation
    Solution:Original question:
     
2921
2
 +
2921
2
 ×
3
100
 +
3
100
 X + (
2921
2
 +
2921
2
 ×
3
100
 +
3
100
 X ) ×
19
400
 × 2 ÷ 2 + (
2921
2
 +
2921
2
 ×
3
100
 +
3
100
 X + (
2921
2
 +
2921
2
 ×
3
100
 +
3
100
 X ) ×
19
400
 × 2 ÷ 2) ×
3
10
 +
131
2500
 = 0
     Left side of the equation =
2921
2
 +
8763
200
 +
3
100
 X + (
2921
2
 +
2921
2
 ×
3
100
 +
3
100
 X ) ×
19
400
 + (
2921
2
 +
2921
2
 ×
3
100
 +
3
100
 X + (
2921
2
 +
2921
2
 ×
3
100
 +
3
100
 X ) ×
19
400
 × 2 ÷ 2) ×
3
10
 +
131
2500
 X
                                             =
300863
200
 +
103
1250
 X + (
2921
2
 +
2921
2
 ×
3
100
 +
3
100
 X ) ×
19
400
 + (
2921
2
 +
2921
2
 ×
3
100
 +
3
100
 X + (
2921
2
 +
2921
2
 ×
3
100
 +
3
100
 X ) ×
19
400
 × 2 ÷ 2) ×
3
10
    The equation is transformed into :
     
300863
200
 +
103
1250
 X + (
2921
2
 +
2921
2
 ×
3
100
 +
3
100
 X ) ×
19
400
 + (
2921
2
 +
2921
2
 ×
3
100
 +
3
100
 X + (
2921
2
 +
2921
2
 ×
3
100
 +
3
100
 X ) ×
19
400
 × 2 ÷ 2) ×
3
10
 = 0
    Remove the bracket on the left of the equation:
     Left side of the equation =
300863
200
 +
103
1250
 X +
2921
2
 ×
19
400
 +
2921
2
 ×
3
100
 ×
19
400
 +
3
100
 X ×
19
400
 + (
2921
2
 +
2921
2
 ×
3
100
 +
3
100
 X + (
2921
2
 +
2921
2
 ×
3
100
 +
3
100
 X ) ×
19
400
 × 2 ÷ 2)
                                             =
300863
200
 +
103
1250
 X +
55499
800
 +
166497
80000
 +
57
40000
 X + (
2921
2
 +
2921
2
 ×
3
100
 +
3
100
 X + (
2921
2
 +
2921
2
 ×
3
100
 +
3
100
 X ) ×
19
400
 × 2 ÷ 2) ×
3
10

    
        X≈-21967.249685 , keep 6 decimal places    
    There are 1 solution(s).

解一元一次方程的详细方法请参阅：《一元一次方程的解法》


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