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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 1/[(1+2x)(1+2x)(1+2x)(1+2x)] = 1-8x .
    Question type: Equation
    Solution:Original question:
     1 ÷ ((1 + 2 x )(1 + 2 x )(1 + 2 x )(1 + 2 x )) = 18 x
     Multiply both sides of the equation by:((1 + 2 x )(1 + 2 x )(1 + 2 x )(1 + 2 x ))
     1 = 1((1 + 2 x )(1 + 2 x )(1 + 2 x )(1 + 2 x ))8 x ((1 + 2 x )(1 + 2 x )(1 + 2 x )(1 + 2 x ))
    Remove a bracket on the right of the equation::
     1 = 1(1 + 2 x )(1 + 2 x )(1 + 2 x )(1 + 2 x )8 x ((1 + 2 x )(1 + 2 x )(1 + 2 x )(1 + 2 x ))
    Remove a bracket on the right of the equation::
     1 = 1 × 1(1 + 2 x )(1 + 2 x )(1 + 2 x ) + 1 × 2 x (1 + 2 x )(1 + 2 x )(1 + 2 x )8
    The equation is reduced to :
     1 = 1(1 + 2 x )(1 + 2 x )(1 + 2 x ) + 2 x (1 + 2 x )(1 + 2 x )(1 + 2 x )8 x ((1 + 2 x )(1 + 2 x )(1 + 2 x )(1 + 2 x ))
    Remove a bracket on the right of the equation::
     1 = 1 × 1(1 + 2 x )(1 + 2 x ) + 1 × 2 x (1 + 2 x )(1 + 2 x ) + 2 x (1 + 2 x )
    The equation is reduced to :
     1 = 1(1 + 2 x )(1 + 2 x ) + 2 x (1 + 2 x )(1 + 2 x ) + 2 x (1 + 2 x )(1 + 2 x )(1 + 2 x )
    Remove a bracket on the right of the equation::
     1 = 1 × 1(1 + 2 x ) + 1 × 2 x (1 + 2 x ) + 2 x (1 + 2 x )(1 + 2 x ) + 2
    The equation is reduced to :
     1 = 1(1 + 2 x ) + 2 x (1 + 2 x ) + 2 x (1 + 2 x )(1 + 2 x ) + 2 x (1 + 2 x )
    Remove a bracket on the right of the equation::
     1 = 1 × 1 + 1 × 2 x + 2 x (1 + 2 x ) + 2 x (1 + 2 x )(1 + 2 x )
    The equation is reduced to :
     1 = 1 + 2 x + 2 x (1 + 2 x ) + 2 x (1 + 2 x )(1 + 2 x ) + 2 x
    Remove a bracket on the right of the equation::
     1 = 1 + 2 x + 2 x × 1 + 2 x × 2 x + 2 x
    The equation is reduced to :
     1 = 1 + 2 x + 2 x + 4 x x + 2 x (1 + 2 x )(1 + 2 x )
    The equation is reduced to :
     1 = 1 + 4 x + 4 x x + 2 x (1 + 2 x )(1 + 2 x ) + 2 x
    Remove a bracket on the right of the equation::
     1 = 1 + 4 x + 4 x x + 2 x × 1(1 + 2 x ) + 2 x
    The equation is reduced to :
     1 = 1 + 4 x + 4 x x + 2 x (1 + 2 x ) + 4 x x
    Remove a bracket on the right of the equation::
     1 = 1 + 4 x + 4 x x + 2 x × 1 + 2 x × 2
    The equation is reduced to :
     1 = 1 + 4 x + 4 x x + 2 x + 4 x x + 4
    The equation is reduced to :
     1 = 1 + 6 x + 4 x x + 4 x x + 4 x x
    Remove a bracket on the right of the equation::
     1 = 1 + 6 x + 4 x x + 4 x x + 4 x x
    The equation is reduced to :
     1 = 1 + 6 x + 4 x x + 4 x x + 4 x x
    Remove a bracket on the right of the equation::
     1 = 1 + 6 x + 4 x x + 4 x x + 4 x x
    The equation is reduced to :
     1 = 1 + 6 x + 4 x x + 4 x x + 4 x x
    Remove a bracket on the right of the equation::
     1 = 1 + 6 x + 4 x x + 4 x x + 4 x x
    The equation is reduced to :
     1 = 1 + 6 x + 4 x x + 4 x x + 4 x x

    After the equation is converted into a general formula, there is a common factor:
    ( x - 0 )( x - 0 )
    From
        x - 0 = 0
        x - 0 = 0

    it is concluded that::
        x1=0
        x2=0

    Solutions that cannot be obtained by factorization:
        x3≈-0.802915 , keep 6 decimal places
    
    There are 3 solution(s).


解程的详细方法请参阅:《方程的解法》



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