Mathematics
         
语言:中文    Language:English
                                Equations   
Fold
                                Unary equation
                                Multivariate equation
                                Math OP  
Unfold
                                Linear algebra      
Unfold
                                Derivative function
                                Function image
                                Hot issues
On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 2.6x+(23-10-x)*3.5 = 81.8-2.6X .
    Question type: Equation
    Solution:Original question:
     
13
5
x + (2310 x ) ×
7
2
=
409
5
13
5
x
    Remove the bracket on the left of the equation:
     Left side of the equation =
13
5
x + 23 ×
7
2
10 ×
7
2
x ×
7
2
                                             =
13
5
x +
161
2
35 x ×
7
2
                                             = -
9
10
x +
91
2
    The equation is transformed into :
      -
9
10
x +
91
2
=
409
5
13
5
x

    Transposition :
      -
9
10
x +
13
5
x =
409
5
91
2

    Combine the items on the left of the equation:
     
17
10
x =
409
5
91
2

    Combine the items on the right of the equation:
     
17
10
x =
363
10

    The coefficient of the unknown number is reduced to 1 :
      x =
363
10
÷
17
10
        =
363
10
×
10
17
        = 363 ×
1
17

    We obtained :
      x =
363
17
    This is the solution of the equation.

    Convert the result to decimal form :
      x = 21.352941



Your problem has not been solved here? Please go to the Hot Problems section!





  New addition:Lenders ToolBox module(Specific location:Math OP > Lenders ToolBox ),welcome。