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On line Solution of Monovariate Equation：
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    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 43×3.45%+（1105-43+44+2%V）×[（1+3.45%）0.5-1] = 0 .
    Question type: Equation
    Solution:Original question:
     43 ×
69
2000
 + (1105 − 43 + 44 +
2
100
 V )((1 +
69
2000
) ×
1
2
 − 1) = 0
     Left side of the equation =
2967
2000
 + (1105 − 43 + 44 +
2
100
 V )((1 +
69
2000
) ×
1
2
 − 1)
    The equation is transformed into :
     
2967
2000
 + (1105 − 43 + 44 +
2
100
 V )((1 +
69
2000
) ×
1
2
 − 1) = 0
    Remove the bracket on the left of the equation:
     Left side of the equation =
2967
2000
 + 1105((1 +
69
2000
) ×
1
2
 − 1) − 43((1 +
69
2000
) ×
1
2
 − 1) + 44((1 +
69
2000
) ×
1
2
 − 1) +
2
100
 V ((1 +
69
2000
) ×
1
2
 − 1)
                                             =
2967
2000
 + 1105(1 +
69
2000
) ×
1
2
 − 1105 × 1 − 43((1 +
69
2000
) ×
1
2
 − 1) + 44((1 +
69
2000
) ×
1
2
 − 1) +
2
100
 V
                                             =
2967
2000
 +
1105
2
(1 +
69
2000
) − 1105 − 43((1 +
69
2000
) ×
1
2
 − 1) + 44((1 +
69
2000
) ×
1
2
 − 1) +
2
100
 V ((1 +
69
2000
) ×
1
2
 − 1)
                                             = -
2207033
2000
 +
1105
2
(1 +
69
2000
) − 43((1 +
69
2000
) ×
1
2
 − 1) + 44((1 +
69
2000
) ×
1
2
 − 1) +
2
100
 V ((1 +
69
2000
) ×
1
2
 − 1)
                                             = -
2207033
2000
 +
1105
2
 × 1 +
1105
2
 ×
69
2000
 − 43((1 +
69
2000
) ×
1
2
 − 1) + 44((1 +
69
2000
) ×
1
2
 − 1) +
2
100
 V ((1 +
69
2000
) ×
1
2
 − 1)
                                             = -
2207033
2000
 +
1105
2
 +
15249
800
 − 43((1 +
69
2000
) ×
1
2
 − 1) + 44((1 +
69
2000
) ×
1
2
 − 1) +
2
100
 V ((1 +
69
2000
) ×
1
2
 − 1)
                                             = -
2127821
4000
 − 43((1 +
69
2000
) ×
1
2
 − 1) + 44((1 +
69
2000
) ×
1
2
 − 1) +
2
100
 V ((1 +
69
2000
) ×
1
2
 − 1)
                                             = -
2127821
4000
 − 43(1 +
69
2000
) ×
1
2
 + 43 × 1 + 44((1 +
69
2000
) ×
1
2
 − 1) +
2
100
 V ((1 +
69
2000
) ×
1
2
 − 1)
                                             = -
2127821
4000
 −
43
2
(1 +
69
2000
) + 43 + 44((1 +
69
2000
) ×
1
2
 − 1) +
2
100
 V ((1 +
69
2000
) ×
1
2
 − 1)
                                             = -
1955821
4000
 −
43
2
(1 +
69
2000
) + 44((1 +
69
2000
) ×
1
2
 − 1) +
2
100
 V ((1 +
69
2000
) ×
1
2
 − 1)
                                             = -
1955821
4000
 −
43
2
 × 1 −
43
2
 ×
69
2000
 + 44((1 +
69
2000
) ×
1
2
 − 1) +
2
100
 V ((1 +
69
2000
) ×
1
2
 − 1)
                                             = -
1955821
4000
 −
43
2
 −
2967
4000
 + 44((1 +
69
2000
) ×
1
2
 − 1) +
2
100
 V ((1 +
69
2000
) ×
1
2
 − 1)
                                             = -
511197
1000
 + 44((1 +
69
2000
) ×
1
2
 − 1) +
2
100
 V ((1 +
69
2000
) ×
1
2
 − 1)
                                             = -
511197
1000
 + 44(1 +
69
2000
) ×
1
2
 − 44 × 1 +
2
100
 V ((1 +
69
2000
) ×
1
2
 − 1)
                                             = -
511197
1000
 + 22(1 +
69
2000
) − 44 +
2
100
 V ((1 +
69
2000
) ×
1
2
 − 1)
                                             = -
555197
1000
 + 22(1 +
69
2000
) +
2
100
 V ((1 +
69
2000
) ×
1
2
 − 1)
                                             = -
555197
1000
 + 22 × 1 + 22 ×
69
2000
 +
2
100
 V ((1 +
69
2000
) ×
1
2
 − 1)
                                             = -
555197
1000
 + 22 +
759
1000
 +
2
100
 V ((1 +
69
2000
) ×
1
2
 − 1)
                                             = -
266219
500
 +
2
100
 V ((1 +
69
2000
) ×
1
2
 − 1)
                                             = -
266219
500
 +
2
100
 V (1 +
69
2000
) ×
1
2
 −
2
100
 V × 1
                                             = -
266219
500
 +
1
100
 V (1 +
69
2000
) −
1
50
 V
                                             = -
266219
500
 +
1
100
 V × 1 +
1
100
 V ×
69
2000
 −
1
50
 V
                                             = -
266219
500
 +
1
100
 V +
69
200000
 V −
1
50
 V

    
        V≈-55146.349042 , keep 6 decimal places    
    There are 1 solution(s).

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