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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 2 questions will be solved this time.Among them
           ☆2 equations

[ 1/2 Equation]
    Work: Find the solution of equation k-(k-(k-1)/2)/2 = 2(k-1)/3 .
    Question type: Equation
    Solution:Original question:
      k ( k ( k 1) ÷ 2) ÷ 2 = 2( k 1) ÷ 3
    Remove the bracket on the left of the equation:
     Left side of the equation = k k ×
1
2
+ ( k 1) ÷ 2 ×
1
2
                                             = k k ×
1
2
+ ( k 1) ×
1
4
                                             =
1
2
k + ( k 1) ×
1
4
                                             =
1
2
k + k ×
1
4
1 ×
1
4
                                             =
1
2
k + k ×
1
4
1
4
                                             =
3
4
k
1
4
    The equation is transformed into :
     
3
4
k
1
4
= 2( k 1) ÷ 3
     Right side of the equation =
2
3
( k 1)
    The equation is transformed into :
     
3
4
k
1
4
=
2
3
( k 1)
    Remove the bracket on the right of the equation:
     Right side of the equation =
2
3
k
2
3
× 1
                                               =
2
3
k
2
3
    The equation is transformed into :
     
3
4
k
1
4
=
2
3
k
2
3

    Transposition :
     
3
4
k
2
3
k = -
2
3
+
1
4

    Combine the items on the left of the equation:
     
1
12
k = -
2
3
+
1
4

    Combine the items on the right of the equation:
     
1
12
k = -
5
12

    The coefficient of the unknown number is reduced to 1 :
      k = -
5
12
÷
1
12
        = -
5
12
× 12
        = - 5 × 1

    We obtained :
      k = - 5
    This is the solution of the equation.

[ 2/2 Equation]
    Work: Find the solution of equation ((((x+2)/3+4)/5+6)/7+8)/9 = 1 .
    Question type: Equation
    Solution:Original question:
     (((( x + 2) ÷ 3 + 4) ÷ 5 + 6) ÷ 7 + 8) ÷ 9 = 1
    Remove the bracket on the left of the equation:
     Left side of the equation = ((( x + 2) ÷ 3 + 4) ÷ 5 + 6) ÷ 7 ×
1
9
+ 8 ×
1
9
                                             = ((( x + 2) ÷ 3 + 4) ÷ 5 + 6) ×
1
63
+
8
9
                                             = (( x + 2) ÷ 3 + 4) ÷ 5 ×
1
63
+ 6 ×
1
63
+
8
9
                                             = (( x + 2) ÷ 3 + 4) ×
1
315
+
2
21
+
8
9
                                             = (( x + 2) ÷ 3 + 4) ×
1
315
+
62
63
                                             = ( x + 2) ÷ 3 ×
1
315
+ 4 ×
1
315
+
62
63
                                             = ( x + 2) ×
1
945
+
4
315
+
62
63
                                             = ( x + 2) ×
1
945
+
314
315
                                             = x ×
1
945
+ 2 ×
1
945
+
314
315
                                             = x ×
1
945
+
2
945
+
314
315
                                             =
1
945
x +
944
945
    The equation is transformed into :
     
1
945
x +
944
945
= 1

    Transposition :
     
1
945
x = 1
944
945

    Combine the items on the right of the equation:
     
1
945
x =
1
945

    The coefficient of the unknown number is reduced to 1 :
      x =
1
945
÷
1
945
        =
1
945
× 945
        = 1 × 1

    We obtained :
      x = 1
    This is the solution of the equation.



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