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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (1000-140)*10+(1000-220)*(x-10) = 800x .
    Question type: Equation
    Solution:Original question:
     (1000140) × 10 + (1000220)( x 10) = 800 x
    Remove the bracket on the left of the equation:
     Left side of the equation = 1000 × 10140 × 10 + (1000220)( x 10)
                                             = 100001400 + (1000220)( x 10)
                                             = 8600 + (1000220)( x 10)
                                             = 8600 + 1000( x 10)220( x 10)
                                             = 8600 + 1000 x 1000 × 10220( x 10)
                                             = 8600 + 1000 x 10000220( x 10)
                                             = - 1400 + 1000 x 220( x 10)
                                             = - 1400 + 1000 x 220 x + 220 × 10
                                             = - 1400 + 1000 x 220 x + 2200
                                             = 800 + 780 x
    The equation is transformed into :
     800 + 780 x = 800 x

    Transposition :
     780 x 800 x = - 800

    Combine the items on the left of the equation:
      - 20 x = - 800

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
     800 = 20 x

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
     20 x = 800

    The coefficient of the unknown number is reduced to 1 :
      x = 800 ÷ 20
        = 800 ×
1
20
        = 40 × 1

    We obtained :
      x = 40
    This is the solution of the equation.



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