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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 1/(x+3) = 1/(x+2)+1/(x+1)+1 .
    Question type: Equation
    Solution:Original question:
     1 ÷ ( x + 3) = 1 ÷ ( x + 2) + 1 ÷ ( x + 1) + 1
     Multiply both sides of the equation by:( x + 3) ,  ( x + 2)
     1( x + 2) = 1( x + 3) + 1 ÷ ( x + 1) × ( x + 3)( x + 2) + 1( x + 3)( x + 2)
    Remove a bracket on the left of the equation::
     1 x + 1 × 2 = 1( x + 3) + 1 ÷ ( x + 1) × ( x + 3)( x + 2) + 1( x + 3)( x + 2)
    Remove a bracket on the right of the equation::
     1 x + 1 × 2 = 1 x + 1 × 3 + 1 ÷ ( x + 1) × ( x + 3)( x + 2) + 1( x + 3)( x + 2)
    The equation is reduced to :
     1 x + 2 = 1 x + 3 + 1 ÷ ( x + 1) × ( x + 3)( x + 2) + 1( x + 3)( x + 2)
     Multiply both sides of the equation by:( x + 1)
     1 x ( x + 1) + 2( x + 1) = 1 x ( x + 1) + 3( x + 1) + 1( x + 3)( x + 2) + 1( x + 3)( x + 2)( x + 1)
    Remove a bracket on the left of the equation:
     1 x x + 1 x × 1 + 2( x + 1) = 1 x ( x + 1) + 3( x + 1) + 1( x + 3)( x + 2) + 1( x + 3)( x + 2)( x + 1)
    Remove a bracket on the right of the equation::
     1 x x + 1 x × 1 + 2( x + 1) = 1 x x + 1 x × 1 + 3( x + 1) + 1( x + 3)( x + 2) + 1
    The equation is reduced to :
     1 x x + 1 x + 2( x + 1) = 1 x x + 1 x + 3( x + 1) + 1( x + 3)( x + 2) + 1( x + 3)
    Remove a bracket on the left of the equation:
     1 x x + 1 x + 2 x + 2 × 1 = 1 x x + 1 x + 3( x + 1) + 1( x + 3)( x + 2) + 1( x + 3)
    Remove a bracket on the right of the equation::
     1 x x + 1 x + 2 x + 2 × 1 = 1 x x + 1 x + 3 x + 3 × 1 + 1( x + 3)( x + 2)
    The equation is reduced to :
     1 x x + 1 x + 2 x + 2 = 1 x x + 1 x + 3 x + 3 + 1( x + 3)( x + 2) + 1
    The equation is reduced to :
     1 x x + 3 x + 2 = 1 x x + 4 x + 3 + 1( x + 3)( x + 2) + 1( x + 3)( x + 2)
    Remove a bracket on the right of the equation::
     1 x x + 3 x + 2 = 1 x x + 4 x + 3 + 1 x ( x + 2) + 1 × 3( x + 2)
    The equation is reduced to :
     1 x x + 3 x + 2 = 1 x x + 4 x + 3 + 1 x ( x + 2) + 3( x + 2) + 1
    Remove a bracket on the right of the equation::
     1 x x + 3 x + 2 = 1 x x + 4 x + 3 + 1 x x + 1 x × 2
    The equation is reduced to :
     1 x x + 3 x + 2 = 1 x x + 4 x + 3 + 1 x x + 2 x + 3
    The equation is reduced to :
     1 x x + 3 x + 2 = 1 x x + 6 x + 3 + 1 x x + 3( x + 2) + 1
    Remove a bracket on the right of the equation::
     1 x x + 3 x + 2 = 1 x x + 6 x + 3 + 1 x x + 3 x + 3
    The equation is reduced to :
     1 x x + 3 x + 2 = 1 x x + 6 x + 3 + 1 x x + 3 x + 6
    The equation is reduced to :
     1 x x + 3 x + 2 = 1 x x + 9 x + 9 + 1 x x + 1( x + 3)( x + 2)
    Remove a bracket on the right of the equation::
     1 x x + 3 x + 2 = 1 x x + 9 x + 9 + 1 x x + 1 x ( x + 2)
    The equation is reduced to :
     1 x x + 3 x + 2 = 1 x x + 9 x + 9 + 1 x x + 1 x ( x + 2)

    
        x≈-1.456311 , keep 6 decimal places
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



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