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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 5(5a+5+5a+10)/2+(5a+5)(a+1)/2+(4-a)(5a+10)/2 = 0 .
    Question type: Equation
    Solution:Original question:
     5(5 a + 5 + 5 a + 10) ÷ 2 + (5 a + 5)( a + 1) ÷ 2 + (4 a )(5 a + 10) ÷ 2 = 0
     Left side of the equation =
5
2
(5 a + 5 + 5 a + 10) + (5 a + 5)( a + 1) ×
1
2
+ (4 a )(5 a + 10) ×
1
2
    The equation is transformed into :
     
5
2
(5 a + 5 + 5 a + 10) + (5 a + 5)( a + 1) ×
1
2
+ (4 a )(5 a + 10) ×
1
2
= 0
    Remove the bracket on the left of the equation:
     Left side of the equation =
5
2
× 5 a +
5
2
× 5 +
5
2
× 5 a +
5
2
× 10 + (5 a + 5)( a + 1)
                                             =
25
2
a +
25
2
+
25
2
a + 25 + (5 a + 5)( a + 1) ×
1
2
+ (4 a )(5 a + 10) ×
1
2
                                             = 25 a +
75
2
+ (5 a + 5)( a + 1) ×
1
2
+ (4 a )(5 a + 10) ×
1
2
                                             = 25 a +
75
2
+ 5 a ( a + 1) ×
1
2
+ 5( a + 1) ×
1
2
+ (4 a )(5 a + 10)
                                             = 25 a +
75
2
+
5
2
a ( a + 1) +
5
2
( a + 1) + (4 a )(5 a + 10) ×
1
2
                                             = 25 a +
75
2
+
5
2
a a +
5
2
a × 1 +
5
2
( a + 1) + (4 a )
                                             = 25 a +
75
2
+
5
2
a a +
5
2
a +
5
2
( a + 1) + (4 a )(5 a + 10)
                                             =
55
2
a +
75
2
+
5
2
a a +
5
2
( a + 1) + (4 a )(5 a + 10) ×
1
2
                                             =
55
2
a +
75
2
+
5
2
a a +
5
2
a +
5
2
× 1 + (4 a )(5 a + 10)
                                             =
55
2
a +
75
2
+
5
2
a a +
5
2
a +
5
2
+ (4 a )(5 a + 10) ×
1
2
                                             = 30 a + 40 +
5
2
a a + (4 a )(5 a + 10) ×
1
2
                                             = 30 a + 40 +
5
2
a a + 4(5 a + 10) ×
1
2
a (5 a + 10) ×
1
2
                                             = 30 a + 40 +
5
2
a a + 2(5 a + 10) a (5 a + 10) ×
1
2
                                             = 30 a + 40 +
5
2
a a + 2 × 5 a + 2 × 10 a
                                             = 30 a + 40 +
5
2
a a + 10 a + 20 a (5 a + 10) ×
1
2
                                             = 40 a + 60 +
5
2
a a a (5 a + 10) ×
1
2
                                             = 40 a + 60 +
5
2
a a a × 5 a ×
1
2
a × 10
                                             = 40 a + 60 +
5
2
a a a ×
5
2
a a × 5
                                             = 35 a + 60 +
5
2
a a a ×
5
2
a
    The equation is transformed into :
     35 a + 60 +
5
2
a a a ×
5
2
a = 0

    the solutions is:
        a=-
12
7
    
    There are 1 solution(s).


解方程的详细方法请参阅:《方程的解法》



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