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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 18-0.5(2v/3+125/3v-5)(2v/3+125/3v-5) = v(2v/3+50/3v-2)-1.25(2v/3+50/3v-2)(2v/3+50/3v-2) .
    Question type: Equation
    Solution:Original question:
     18
1
2
(2 v ÷ 3 + 125 ÷ 3 × v 5)(2 v ÷ 3 + 125 ÷ 3 × v 5) = v (2 v ÷ 3 + 50 ÷ 3 × v 2)
5
4
(2 v ÷ 3 + 50 ÷ 3 × v 2)(2 v ÷ 3 + 50 ÷ 3 × v 2)
    Remove the bracket on the left of the equation:
     Left side of the equation = 18
1
2
× 2 v ÷ 3 × (2 v ÷ 3 + 125 ÷ 3 × v 5)
1
2
× 125 ÷ 3 × v (2 v ÷ 3 + 125 ÷ 3 × v 5) +
1
2
                                             = 18
1
3
v (2 v ÷ 3 + 125 ÷ 3 × v 5)
125
6
v (2 v ÷ 3 + 125 ÷ 3 × v 5) +
5
2
(2 v ÷ 3 + 125 ÷ 3 × v 5)
                                             = 18
1
3
v × 2 v ÷ 3
1
3
v × 125 ÷ 3 × v +
1
3
                                             = 18
2
9
v v
125
9
v v +
5
3
v
125
6
v (2 v ÷ 3 + 125 ÷ 3 × v 5)
                                             = 18
2
9
v v
125
9
v v +
5
3
v
125
6
v × 2
                                             = 18
2
9
v v
125
9
v v +
5
3
v
125
9
v v
                                             = 18
2
9
v v
125
9
v v +
635
6
v
125
9
v v
                                             = 18
2
9
v v
125
9
v v +
635
6
v
125
9
v v
                                             = 18
2
9
v v
125
9
v v +
635
6
v
125
9
v v
                                             =
11
2
2
9
v v
125
9
v v +
635
3
v
125
9
v v
    The equation is transformed into :
     
11
2
2
9
v v
125
9
v v +
635
3
v
125
9
v v = v (2 v ÷ 3 + 50 ÷ 3 × v 2)
5
4
(2 v ÷ 3 + 50 ÷ 3 × v 2)(2 v ÷ 3 + 50 ÷ 3 × v 2)
    Remove the bracket on the right of the equation:
     Right side of the equation = v × 2 v ÷ 3 + v × 50 ÷ 3 × v v × 2
5
4
(2 v ÷ 3 + 50 ÷ 3 × v 2)
                                               = v ×
2
3
v + v ×
50
3
v v × 2
5
4
(2 v ÷ 3 + 50 ÷ 3 × v 2)(2 v ÷ 3 + 50 ÷ 3 × v 2)
                                               = v ×
2
3
v + v ×
50
3
v 2 v
5
4
× 2 v ÷ 3
                                               = v ×
2
3
v + v ×
50
3
v 2 v
5
6
v (2 v ÷ 3 + 50 ÷ 3 × v 2)
125
6
                                               = v ×
2
3
v + v ×
50
3
v 2 v
5
6
v × 2 v
                                               = v ×
2
3
v + v ×
50
3
v 2 v
5
9
v v
125
9
                                               = v ×
2
3
v + v ×
50
3
v
1
3
v
5
9
v v
125
9
                                               = v ×
2
3
v + v ×
50
3
v
1
3
v
5
9
v v
125
9
                                               = v ×
2
3
v + v ×
50
3
v
1
3
v
5
9
v v
125
9
                                               = v ×
2
3
v + v ×
50
3
v +
124
3
v
5
9
v v
125
9
                                               = v ×
2
3
v + v ×
50
3
v +
124
3
v
5
9
v v
125
9
                                               = v ×
2
3
v + v ×
50
3
v +
124
3
v
5
9
v v
125
9
                                               = v ×
2
3
v + v ×
50
3
v +
254
3
v
5
9
v v
125
9
    The equation is transformed into :
     
11
2
2
9
v v
125
9
v v +
635
3
v
125
9
v v = v ×
2
3
v + v ×
50
3
v +
254
3
v
5
9
v v
125
9
    The equation can be reduced to :
     
11
2
2
9
v v
125
9
v v +
635
3
v
125
9
v v = v ×
2
3
v + v ×
50
3
v +
254
3
v
5
9
v v
125
9

    The solution of the equation:
        v1≈-0.064861 , keep 6 decimal places
        v2≈0.300994 , keep 6 decimal places
    
    There are 2 solution(s).


解程的详细方法请参阅:《方程的解法》



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