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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 6 questions will be solved this time.Among them
           ☆6 equations

[ 1/6 Equation]
    Work: Find the solution of equation 4x×3-2x-19 = 51 .
    Question type: Equation
    Solution:Original question:
     4 x × 32 x 19 = 51
     Left side of the equation = 12 x 2 x 19
                                             = 10 x 19
    The equation is transformed into :
     10 x 19 = 51

    Transposition :
     10 x = 51 + 19

    Combine the items on the right of the equation:
     10 x = 70

    The coefficient of the unknown number is reduced to 1 :
      x = 70 ÷ 10
        = 70 ×
1
10
        = 7 × 1

    We obtained :
      x = 7
    This is the solution of the equation.

[ 2/6 Equation]
    Work: Find the solution of equation (2x-2)÷3 = 16 .
    Question type: Equation
    Solution:Original question:
     (2 x 2) ÷ 3 = 16
    Remove the bracket on the left of the equation:
     Left side of the equation = 2 x ×
1
3
2 ×
1
3
                                             =
2
3
x
2
3
    The equation is transformed into :
     
2
3
x
2
3
= 16

    Transposition :
     
2
3
x = 16 +
2
3

    Combine the items on the right of the equation:
     
2
3
x =
50
3

    The coefficient of the unknown number is reduced to 1 :
      x =
50
3
÷
2
3
        =
50
3
×
3
2
        = 25 × 1

    We obtained :
      x = 25
    This is the solution of the equation.

[ 3/6 Equation]
    Work: Find the solution of equation 3(x+5) = 24 .
    Question type: Equation
    Solution:Original question:
     3( x + 5) = 24
    Remove the bracket on the left of the equation:
     Left side of the equation = 3 x + 3 × 5
                                             = 3 x + 15
    The equation is transformed into :
     3 x + 15 = 24

    Transposition :
     3 x = 2415

    Combine the items on the right of the equation:
     3 x = 9

    The coefficient of the unknown number is reduced to 1 :
      x = 9 ÷ 3
        = 9 ×
1
3
        = 3 × 1

    We obtained :
      x = 3
    This is the solution of the equation.

[ 4/6 Equation]
    Work: Find the solution of equation 4x×3+33 = 73+2x .
    Question type: Equation
    Solution:Original question:
     4 x × 3 + 33 = 73 + 2 x
     Left side of the equation = 12 x + 33
    The equation is transformed into :
     12 x + 33 = 73 + 2 x

    Transposition :
     12 x 2 x = 7333

    Combine the items on the left of the equation:
     10 x = 7333

    Combine the items on the right of the equation:
     10 x = 40

    The coefficient of the unknown number is reduced to 1 :
      x = 40 ÷ 10
        = 40 ×
1
10
        = 4 × 1

    We obtained :
      x = 4
    This is the solution of the equation.

[ 5/6 Equation]
    Work: Find the solution of equation 5x×2+4x-14 = 252 .
    Question type: Equation
    Solution:Original question:
     5 x × 2 + 4 x 14 = 252
     Left side of the equation = 10 x + 4 x 14
                                             = 14 x 14
    The equation is transformed into :
     14 x 14 = 252

    Transposition :
     14 x = 252 + 14

    Combine the items on the right of the equation:
     14 x = 266

    The coefficient of the unknown number is reduced to 1 :
      x = 266 ÷ 14
        = 266 ×
1
14
        = 19 × 1

    We obtained :
      x = 19
    This is the solution of the equation.

[ 6/6 Equation]
    Work: Find the solution of equation 2x×4+36 = 166-5x .
    Question type: Equation
    Solution:Original question:
     2 x × 4 + 36 = 1665 x
     Left side of the equation = 8 x + 36
    The equation is transformed into :
     8 x + 36 = 1665 x

    Transposition :
     8 x + 5 x = 16636

    Combine the items on the left of the equation:
     13 x = 16636

    Combine the items on the right of the equation:
     13 x = 130

    The coefficient of the unknown number is reduced to 1 :
      x = 130 ÷ 13
        = 130 ×
1
13
        = 10 × 1

    We obtained :
      x = 10
    This is the solution of the equation.



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