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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 6 questions will be solved this time.Among them
           ☆6 equations

[ 1/6 Equation]
    Work: Find the solution of equation 4x+23 = 65-3x .
    Question type: Equation
    Solution:Original question:
     4 x + 23 = 653 x

    Transposition :
     4 x + 3 x = 6523

    Combine the items on the left of the equation:
     7 x = 6523

    Combine the items on the right of the equation:
     7 x = 42

    The coefficient of the unknown number is reduced to 1 :
      x = 42 ÷ 7
        = 42 ×
1
7
        = 6 × 1

    We obtained :
      x = 6
    This is the solution of the equation.

[ 2/6 Equation]
    Work: Find the solution of equation 3x×3-3x-50 = 22 .
    Question type: Equation
    Solution:Original question:
     3 x × 33 x 50 = 22
     Left side of the equation = 9 x 3 x 50
                                             = 6 x 50
    The equation is transformed into :
     6 x 50 = 22

    Transposition :
     6 x = 22 + 50

    Combine the items on the right of the equation:
     6 x = 72

    The coefficient of the unknown number is reduced to 1 :
      x = 72 ÷ 6
        = 72 ×
1
6
        = 12 × 1

    We obtained :
      x = 12
    This is the solution of the equation.

[ 3/6 Equation]
    Work: Find the solution of equation 2x×3+x×4-37 = 33 .
    Question type: Equation
    Solution:Original question:
     2 x × 3 + x × 437 = 33
     Left side of the equation = 6 x + x × 437
                                             = 10 x 37
    The equation is transformed into :
     10 x 37 = 33

    Transposition :
     10 x = 33 + 37

    Combine the items on the right of the equation:
     10 x = 70

    The coefficient of the unknown number is reduced to 1 :
      x = 70 ÷ 10
        = 70 ×
1
10
        = 7 × 1

    We obtained :
      x = 7
    This is the solution of the equation.

[ 4/6 Equation]
    Work: Find the solution of equation 18+3x×3 = 2x×3+24 .
    Question type: Equation
    Solution:Original question:
     18 + 3 x × 3 = 2 x × 3 + 24
     Left side of the equation = 18 + 9 x
    The equation is transformed into :
     18 + 9 x = 2 x × 3 + 24
     Right side of the equation = 6 x + 24
    The equation is transformed into :
     18 + 9 x = 6 x + 24

    Transposition :
     9 x 6 x = 2418

    Combine the items on the left of the equation:
     3 x = 2418

    Combine the items on the right of the equation:
     3 x = 6

    The coefficient of the unknown number is reduced to 1 :
      x = 6 ÷ 3
        = 6 ×
1
3
        = 2 × 1

    We obtained :
      x = 2
    This is the solution of the equation.

[ 5/6 Equation]
    Work: Find the solution of equation 2x+23×4 = 134 .
    Question type: Equation
    Solution:Original question:
     2 x + 23 × 4 = 134
     Left side of the equation = 2 x + 92
    The equation is transformed into :
     2 x + 92 = 134

    Transposition :
     2 x = 13492

    Combine the items on the right of the equation:
     2 x = 42

    The coefficient of the unknown number is reduced to 1 :
      x = 42 ÷ 2
        = 42 ×
1
2
        = 21 × 1

    We obtained :
      x = 21
    This is the solution of the equation.

[ 6/6 Equation]
    Work: Find the solution of equation 8x+44 = 172-4x×2 .
    Question type: Equation
    Solution:Original question:
     8 x + 44 = 1724 x × 2
     Right side of the equation = 1728 x
    The equation is transformed into :
     8 x + 44 = 1728 x

    Transposition :
     8 x + 8 x = 17244

    Combine the items on the left of the equation:
     16 x = 17244

    Combine the items on the right of the equation:
     16 x = 128

    The coefficient of the unknown number is reduced to 1 :
      x = 128 ÷ 16
        = 128 ×
1
16
        = 8 × 1

    We obtained :
      x = 8
    This is the solution of the equation.



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