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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 6 questions will be solved this time.Among them
           ☆6 equations

[ 1/6 Equation]
    Work: Find the solution of equation 4x×4+3x×5-24 = 193 .
    Question type: Equation
    Solution:Original question:
     4 x × 4 + 3 x × 524 = 193
     Left side of the equation = 16 x + 15 x 24
                                             = 31 x 24
    The equation is transformed into :
     31 x 24 = 193

    Transposition :
     31 x = 193 + 24

    Combine the items on the right of the equation:
     31 x = 217

    The coefficient of the unknown number is reduced to 1 :
      x = 217 ÷ 31
        = 217 ×
1
31
        = 7 × 1

    We obtained :
      x = 7
    This is the solution of the equation.

[ 2/6 Equation]
    Work: Find the solution of equation 5x×2+3x×2-22 = 234 .
    Question type: Equation
    Solution:Original question:
     5 x × 2 + 3 x × 222 = 234
     Left side of the equation = 10 x + 6 x 22
                                             = 16 x 22
    The equation is transformed into :
     16 x 22 = 234

    Transposition :
     16 x = 234 + 22

    Combine the items on the right of the equation:
     16 x = 256

    The coefficient of the unknown number is reduced to 1 :
      x = 256 ÷ 16
        = 256 ×
1
16
        = 16 × 1

    We obtained :
      x = 16
    This is the solution of the equation.

[ 3/6 Equation]
    Work: Find the solution of equation 2x×5+26 = 154-6x .
    Question type: Equation
    Solution:Original question:
     2 x × 5 + 26 = 1546 x
     Left side of the equation = 10 x + 26
    The equation is transformed into :
     10 x + 26 = 1546 x

    Transposition :
     10 x + 6 x = 15426

    Combine the items on the left of the equation:
     16 x = 15426

    Combine the items on the right of the equation:
     16 x = 128

    The coefficient of the unknown number is reduced to 1 :
      x = 128 ÷ 16
        = 128 ×
1
16
        = 8 × 1

    We obtained :
      x = 8
    This is the solution of the equation.

[ 4/6 Equation]
    Work: Find the solution of equation 5x×2+10 = 23-3x .
    Question type: Equation
    Solution:Original question:
     5 x × 2 + 10 = 233 x
     Left side of the equation = 10 x + 10
    The equation is transformed into :
     10 x + 10 = 233 x

    Transposition :
     10 x + 3 x = 2310

    Combine the items on the left of the equation:
     13 x = 2310

    Combine the items on the right of the equation:
     13 x = 13

    The coefficient of the unknown number is reduced to 1 :
      x = 13 ÷ 13
        = 13 ×
1
13
        = 1 × 1

    We obtained :
      x = 1
    This is the solution of the equation.

[ 5/6 Equation]
    Work: Find the solution of equation 3x×2+38 = 228-2x×2 .
    Question type: Equation
    Solution:Original question:
     3 x × 2 + 38 = 2282 x × 2
     Left side of the equation = 6 x + 38
    The equation is transformed into :
     6 x + 38 = 2282 x × 2
     Right side of the equation = 2284 x
    The equation is transformed into :
     6 x + 38 = 2284 x

    Transposition :
     6 x + 4 x = 22838

    Combine the items on the left of the equation:
     10 x = 22838

    Combine the items on the right of the equation:
     10 x = 190

    The coefficient of the unknown number is reduced to 1 :
      x = 190 ÷ 10
        = 190 ×
1
10
        = 19 × 1

    We obtained :
      x = 19
    This is the solution of the equation.

[ 6/6 Equation]
    Work: Find the solution of equation (x-3)÷2 = 7.5 .
    Question type: Equation
    Solution:Original question:
     ( x 3) ÷ 2 =
15
2
    Remove the bracket on the left of the equation:
     Left side of the equation = x ×
1
2
3 ×
1
2
                                             = x ×
1
2
3
2
    The equation is transformed into :
     
1
2
x
3
2
=
15
2

    Transposition :
     
1
2
x =
15
2
+
3
2

    Combine the items on the right of the equation:
     
1
2
x = 9

    The coefficient of the unknown number is reduced to 1 :
      x = 9 ÷
1
2
        = 9 × 2

    We obtained :
      x = 18
    This is the solution of the equation.



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