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It supports mathematical functions (including trigonometric functions).
Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation 0.5*(5-2t)*0.6*(4-t) = 0 .
Question type: Equation
Solution:Original question:
The equation is transformed into :
Remove the bracket on the left of the equation:
The equation is transformed into :
After the equation is converted into a general formula, it is converted into:
( 2t - 5 )( t - 4 )=0
From
2t - 5 = 0
t - 4 = 0
it is concluded that:：
There are 2 solution(s).
解一元二次方程的详细方法请参阅：《一元二次方程的解法》
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation 0.5*(5-2t)*0.6*(4-t) = 0 .
Question type: Equation
Solution:Original question:
1 2 | ( | 5 | − | 2 | t | ) | × | 3 5 | ( | 4 | − | t | ) | = | 0 |
| Left side of the equation = | 3 10 | ( | 5 | − | 2 | t | ) | ( | 4 | − | t | ) |
3 10 | ( | 5 | − | 2 | t | ) | ( | 4 | − | t | ) | = | 0 |
| Left side of the equation = | 3 10 | × | 5 | ( | 4 | − | t | ) | − | 3 10 | × | 2 | t | ( | 4 | − | t | ) |
| = | 3 2 | ( | 4 | − | t | ) | − | 3 5 | t | ( | 4 | − | t | ) |
| = | 3 2 | × | 4 | − | 3 2 | t | − | 3 5 | t | ( | 4 | − | t | ) |
| = | 6 | − | 3 2 | t | − | 3 5 | t | ( | 4 | − | t | ) |
| = | 6 | − | 3 2 | t | − | 3 5 | t | × | 4 | + | 3 5 | t | t |
| = | 6 | − | 3 2 | t | − | 12 5 | t | + | 3 5 | t | t |
| = | 6 | − | 39 10 | t | + | 3 5 | t | t |
| 6 | − | 39 10 | t | + | 3 5 | t | t | = | 0 |
After the equation is converted into a general formula, it is converted into:
( 2t - 5 )( t - 4 )=0
From
2t - 5 = 0
t - 4 = 0
it is concluded that:：
| t1= | 5 2 |
| t2=4 |
There are 2 solution(s).
解一元二次方程的详细方法请参阅：《一元二次方程的解法》