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It supports mathematical functions (including trigonometric functions).
Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation （x-12-32）0.7/40 = （x-6-24）0.7/60 .
Question type: Equation
Solution:Original question:
The equation is transformed into :
Remove the bracket on the left of the equation:
The equation is transformed into :
The equation is transformed into :
Remove the bracket on the right of the equation:
The equation is transformed into :
Transposition :
Combine the items on the left of the equation:
Combine the items on the right of the equation:
The coefficient of the unknown number is reduced to 1 :
We obtained :
This is the solution of the equation.
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation （x-12-32）0.7/40 = （x-6-24）0.7/60 .
Question type: Equation
Solution:Original question:
| ( | x | − | 12 | − | 32 | ) | × | 7 10 | ÷ | 40 | = | ( | x | − | 6 | − | 24 | ) | × | 7 10 | ÷ | 60 |
| Left side of the equation = | ( | x | − | 12 | − | 32 | ) | × | 7 400 |
| ( | x | − | 12 | − | 32 | ) | × | 7 400 | = | ( | x | − | 6 | − | 24 | ) | × | 7 10 | ÷ | 60 |
| Left side of the equation = | x | × | 7 400 | − | 12 | × | 7 400 | − | 32 | × | 7 400 |
| = | x | × | 7 400 | − | 21 100 | − | 14 25 |
| = | 7 400 | x | − | 77 100 |
7 400 | x | − | 77 100 | = | ( | x | − | 6 | − | 24 | ) | × | 7 10 | ÷ | 60 |
| Right side of the equation = | ( | x | − | 6 | − | 24 | ) | × | 7 600 |
7 400 | x | − | 77 100 | = | ( | x | − | 6 | − | 24 | ) | × | 7 600 |
| Right side of the equation = | x | × | 7 600 | − | 6 | × | 7 600 | − | 24 | × | 7 600 |
| = | x | × | 7 600 | − | 7 100 | − | 7 25 |
| = | 7 600 | x | − | 7 20 |
7 400 | x | − | 77 100 | = | 7 600 | x | − | 7 20 |
Transposition :
7 400 | x | − | 7 600 | x | = | - | 7 20 | + | 77 100 |
Combine the items on the left of the equation:
7 1200 | x | = | - | 7 20 | + | 77 100 |
Combine the items on the right of the equation:
7 1200 | x | = | 21 50 |
The coefficient of the unknown number is reduced to 1 :
| x | = | 21 50 | ÷ | 7 1200 |
| = | 21 50 | × | 1200 7 |
| = | 3 | × | 24 |
We obtained :
| x | = | 72 |