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Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation （x-20）（50-（x-180）/10） = 10890 .
Question type: Equation
Solution:Original question:
Remove the bracket on the left of the equation:
The equation is transformed into :
After the equation is converted into a general formula, it is converted into:
( 1x - 350 )( 1x - 350 )=0
From
1x - 350 = 0
1x - 350 = 0
it is concluded that:：
x1=350
x2=350
There are 2 solution(s).
解一元二次方程的详细方法请参阅：《一元二次方程的解法》
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation （x-20）（50-（x-180）/10） = 10890 .
Question type: Equation
Solution:Original question:
| ( | x | − | 20 | ) | ( | 50 | − | ( | x | − | 180 | ) | ÷ | 10 | ) | = | 10890 |
| Left side of the equation = | x | ( | 50 | − | ( | x | − | 180 | ) | ÷ | 10 | ) | − | 20 | ( | 50 | − | ( | x | − | 180 | ) | ÷ | 10 | ) |
| = | x | × | 50 | − | x | ( | x | − | 180 | ) | ÷ | 10 | − | 20 | ( | 50 | − | ( | x | − | 180 | ) | ÷ | 10 | ) |
| = | 50 | x | − | x | x | × | 1 10 | + | x | × | 180 | × | 1 10 | − | 20 | ( | 50 | − | ( | x | − | 180 | ) | ÷ | 10 | ) |
| = | 50 | x | − | x | x | × | 1 10 | + | x | × | 18 | − | 20 | ( | 50 | − | ( | x | − | 180 | ) | ÷ | 10 | ) |
| = | 68 | x | − | x | x | × | 1 10 | − | 20 | ( | 50 | − | ( | x | − | 180 | ) | ÷ | 10 | ) |
| = | 68 | x | − | x | x | × | 1 10 | − | 20 | × | 50 | + | 20 | ( | x | − | 180 | ) | ÷ | 10 |
| = | 68 | x | − | x | x | × | 1 10 | − | 1000 | + | 2 | ( | x | − | 180 | ) |
| = | 68 | x | − | x | x | × | 1 10 | − | 1000 | + | 2 | x | − | 2 | × | 180 |
| = | 68 | x | − | x | x | × | 1 10 | − | 1000 | + | 2 | x | − | 360 |
| = | 70 | x | − | x | x | × | 1 10 | − | 1360 |
| 70 | x | − | x | x | × | 1 10 | − | 1360 | = | 10890 |
After the equation is converted into a general formula, it is converted into:
( 1x - 350 )( 1x - 350 )=0
From
1x - 350 = 0
1x - 350 = 0
it is concluded that:：
x1=350
x2=350
There are 2 solution(s).
解一元二次方程的详细方法请参阅：《一元二次方程的解法》