Mathematics
         
语言:中文    Language:English
                                Equations   
Unfold
                                Math OP  
Fold
                                Inequality
                                Mathematics
                                Fractions
                                Statistics
                                Prime factor
                                Fraction and Decimal Interactions
                                Lenders ToolBox
                                Linear algebra      
Unfold
                                Derivative function
                                Function image
                                Hot issues
Mathematical calculation:
    Enter the mathematical formula directly and click the "Next" button to get the calculation answer.
    It supports mathematical functions (including trigonometric functions).
    Current location:Mathematical operation > History of Mathematical Computation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 arithmetic calculations

[1/1 Formula]
    Work: Calculate the value of equation 2/3*1*14.3*π*400^3*(sin(180*0.2436))^3/π .
    Question type: Mathematical calculation
    Solution:
          2/3*1*14.3*π*400^3*(sin(180*0.2436))^3/π
        =2/3*1*14.3*π*400^3*(sin43.848)^3/π
        =2/3*1*14.3*π*400^3*(-0.133894)^3/π
        =2/3*1*14.3*π*64000000*(-0.133894)^3/π
        =2/3*1*14.3*π*64000000*-0.002400398507681/π
        =0.666667*1*14.3*π*64000000*(-0.002400398507681)/π
        =0.666667*14.3*π*64000000*(-0.002400398507681)/π
        =9.533338*π*64000000*(-0.002400398507681)/π
        =29.949865*64000000*(-0.002400398507681)/π
        =1916791360*(-0.002400398507681)/π
        =(-4601063.12008)/π
        =(-1464563.878077)

    Answer:2/3*1*14.3*π*400^3*(sin(180*0.2436))^3/π=-1464563.878077
    Note: Radian


Your problem has not been solved here? Please go to the Hot Problems section!





  New addition:Lenders ToolBox module(Specific location:Math OP > Lenders ToolBox ),welcome。