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Enter the mathematical formula directly and click the "Next" button to get the calculation answer.
It supports mathematical functions (including trigonometric functions).
Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation (a×a+1)(a×a+1)-4a×a = 0 .
Question type: Equation
Solution:Original question:
Remove the bracket on the left of the equation:
The equation is transformed into :
After the equation is converted into a general formula, it is converted into:
( a + 1 )( a + 1 )( a - 1 )( a - 1 )=0
From
a + 1 = 0
a + 1 = 0
a - 1 = 0
a - 1 = 0
it is concluded that:：
a1=-1
a2=-1
a3=1
a4=1
There are 4 solution(s).
解程的详细方法请参阅：《方程的解法》
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation (a×a+1)(a×a+1)-4a×a = 0 .
Question type: Equation
Solution:Original question:
| ( | a | a | + | 1 | ) | ( | a | a | + | 1 | ) | − | 4 | a | a | = | 0 |
| Left side of the equation = | a | a | ( | a | a | + | 1 | ) | + | 1 | ( | a | a | + | 1 | ) | − | 4 | a | a |
| = | a | a | a | a | + | a | a | × | 1 | + | 1 | ( | a | a | + | 1 | ) | − | 4 | a | a |
| = | a | a | a | a | + | a | a | × | 1 | + | 1 | a | a | + | 1 | × | 1 |
| = | a | a | a | a | + | a | a | × | 1 | + | 1 | a | a | + | 1 | − | 4 |
| a | a | a | a | + | a | a | × | 1 | + | 1 | a | a | + | 1 | − | 4 | = | 0 |
After the equation is converted into a general formula, it is converted into:
( a + 1 )( a + 1 )( a - 1 )( a - 1 )=0
From
a + 1 = 0
a + 1 = 0
a - 1 = 0
a - 1 = 0
it is concluded that:：
a1=-1
a2=-1
a3=1
a4=1
There are 4 solution(s).
解程的详细方法请参阅：《方程的解法》