detailed information: The input equation set is: Question solving process:
Divide the two sides of equation (1) by 4, the equation can be obtained: | | -1 | x | + | | | 1 4 | y | + | | | 3 4 | z | = | | - | 55 4 | (4) | , then add the two sides of equation (4) to both sides of equation (2), the equations are reduced to:
 | | | | | - | 27 4 | y | + | | | 27 4 | z | = | | - | 275 4 | | (2) |
| |
Divide the two sides of equation (1) by 4, the equation can be obtained: | | -1 | x | + | | | 1 4 | y | + | | | 3 4 | z | = | | - | 55 4 | (5) | , then add the two sides of equation (5) to both sides of equation (3), the equations are reduced to:
 | | | | | - | 27 4 | y | + | | | 27 4 | z | = | | - | 275 4 | | (2) |
| |
Divide the two sides of equation (2) by 3, the equation can be obtained: | | - | 9 4 | y | + | | | 9 4 | z | = | | - | 275 12 | (6) | , then add the two sides of equation (6) to both sides of equation (3), the equations are reduced to:
 | | | | | - | 27 4 | y | + | | | 27 4 | z | = | | - | 275 4 | | (2) |
| |
Multiply both sides of equation (3) by 27 Divide both sides of equation (3) by 16, get the equation:, then add the two sides of equation (7) to both sides of equation (2), get the equation:
Multiply both sides of equation (3) by 3 Divide both sides of equation (3) by 4, get the equation:, then add the two sides of equation (8) to both sides of equation (1), get the equation:
Multiply both sides of equation (2) by 4 Divide both sides of equation (2) by 27, get the equation:, then add the two sides of equation (9) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |