detailed information: The input equation set is:
 | | | | | 2 | A | + | | 2 | B | + | | C | + | | 2 | D | + | | 2 | E | + | | 2 | F | = | | | 4329 5 | | (1) |
| | | 2 | A | + | | B | + | | | 1 2 | C | + | | 2 | D | + | | 2 | E | + | | 2 | F | = | | | 6151 10 | | (2) |
| | | 2 | A | + | | 2 | B | + | | | 1 2 | C | + | | 2 | D | + | | 2 | E | + | | F | = | | | 6267 10 | | (3) |
| | | A | + | | 2 | D | + | | 2 | E | + | | F | = | | | 5017 10 | | (4) |
| | | Question solving process:
Subtract both sides of equation (1) from both sides of equation (2) ,the equations are reduced to:
 | | | | | 2 | A | + | | 2 | B | + | | C | + | | 2 | D | + | | 2 | E | + | | 2 | F | = | | | 4329 5 | | (1) |
| | | | 2 | A | + | | 2 | B | + | | | 1 2 | C | + | | 2 | D | + | | 2 | E | + | | F | = | | | 6267 10 | | (3) |
| | | A | + | | 2 | D | + | | 2 | E | + | | F | = | | | 5017 10 | | (4) |
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Subtract both sides of equation (1) from both sides of equation (3) ,the equations are reduced to:
 | | | | | 2 | A | + | | 2 | B | + | | C | + | | 2 | D | + | | 2 | E | + | | 2 | F | = | | | 4329 5 | | (1) |
| | | | | A | + | | 2 | D | + | | 2 | E | + | | F | = | | | 5017 10 | | (4) |
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Divide the two sides of equation (1) by 2, the equation can be obtained: | | | A | + | | B | + | | | 1 2 | C | + | | D | + | | E | + | | F | = | | | 4329 10 | (7) | , then subtract both sides of equation (7) from both sides of equation (4), the equations are reduced to:
 | | | | | 2 | A | + | | 2 | B | + | | C | + | | 2 | D | + | | 2 | E | + | | 2 | F | = | | | 4329 5 | | (1) |
| | | | -1 | B | | - | 1 2 | C | + | | D | + | | E | = | | | 344 5 | | (4) |
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Subtract both sides of equation (2) from both sides of equation (4) ,the equations are reduced to:
 | | | | | 2 | A | + | | 2 | B | + | | C | + | | 2 | D | + | | 2 | E | + | | 2 | F | = | | | 4329 5 | | (1) |
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Add both sides of equation (6) to both sides of equation (3), get the equation:
 | | | | | 2 | A | + | | 2 | B | + | | C | + | | 2 | D | + | | 2 | E | + | | 2 | F | = | | | 4329 5 | | (1) |
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Multiply both sides of equation (6) by 2, get the equation:, then subtract both sides of equation (8) from both sides of equation (1), get the equation:
 | | | | | 2 | A | + | | 2 | B | + | | C | + | | 2 | D | + | | 2 | E | = | | | 4179 5 | | (1) |
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Subtract both sides of equation (5) from both sides of equation (4), get the equation:
 | | | | | 2 | A | + | | 2 | B | + | | C | + | | 2 | D | + | | 2 | E | = | | | 4179 5 | | (1) |
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Multiply both sides of equation (5) by 2, get the equation:, then subtract both sides of equation (9) from both sides of equation (1), get the equation:
 | | | | | 2 | A | + | | 2 | B | + | | C | + | | 2 | D | = | | | 3629 5 | | (1) |
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Multiply both sides of equation (4) by 2, get the equation:, then subtract both sides of equation (10) from both sides of equation (1), get the equation:
Subtract both sides of equation (3) from both sides of equation (2), get the equation:
Multiply both sides of equation (3) by 2, get the equation:, then add the two sides of equation (11) to both sides of equation (1), get the equation:
Multiply both sides of equation (2) by 2, get the equation:, then add the two sides of equation (12) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |