detailed information: The input equation set is:
 | | | | | | -1 | A | | -1 | B | + | | 4 | C | + | | D | | -3 | E | = | | 0 | | (3) |
| | | Question solving process:
Divide the two sides of equation (1) by 3, the equation can be obtained: | | | A | | - | 1 3 | B | | - | 1 3 | C | | - | 1 3 | D | = | | | 7 3 | (6) | , then add the two sides of equation (6) to both sides of equation (3), the equations are reduced to:
 | | | | | | - | 4 3 | B | + | | | 11 3 | C | + | | | 2 3 | D | | -3 | E | = | | | 7 3 | | (3) |
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Divide the two sides of equation (1) by 3, the equation can be obtained: | | | A | | - | 1 3 | B | | - | 1 3 | C | | - | 1 3 | D | = | | | 7 3 | (7) | , then subtract both sides of equation (7) from both sides of equation (4), the equations are reduced to:
 | | | | | | - | 4 3 | B | + | | | 11 3 | C | + | | | 2 3 | D | | -3 | E | = | | | 7 3 | | (3) |
| | | | 1 3 | B | | - | 2 3 | C | | - | 2 3 | D | + | | E | = | | - | 7 3 | | (4) |
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Multiply both sides of equation (2) by 4 Divide the two sides of equation (2) by 3, the equation can be obtained: , then add the two sides of equation (8) to both sides of equation (3), the equations are reduced to:
 | | | | | | | | | 1 3 | B | | - | 2 3 | C | | - | 2 3 | D | + | | E | = | | - | 7 3 | | (4) |
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Divide the two sides of equation (2) by 3, the equation can be obtained: , then subtract both sides of equation (9) from both sides of equation (4), the equations are reduced to:
 | | | | | | | - | 2 3 | C | | - | 2 3 | D | + | | E | = | | - | 23 3 | | (4) |
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Multiply both sides of equation (3) by 2 Divide the two sides of equation (3) by 11, the equation can be obtained: | | | | 2 3 | C | + | | | 4 33 | D | | - | 6 11 | E | = | | | 142 33 | (10) | , then add the two sides of equation (10) to both sides of equation (4), the equations are reduced to:
 | | | | | | | - | 6 11 | D | + | | | 5 11 | E | = | | - | 37 11 | | (4) |
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Multiply both sides of equation (3) by 3 Divide the two sides of equation (3) by 11, the equation can be obtained: | | | C | + | | | 2 11 | D | | - | 9 11 | E | = | | | 71 11 | (11) | , then add the two sides of equation (11) to both sides of equation (5), the equations are reduced to:
 | | | | | | | - | 6 11 | D | + | | | 5 11 | E | = | | - | 37 11 | | (4) |
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Multiply both sides of equation (4) by 13 Divide the two sides of equation (4) by 6, the equation can be obtained: | | - | 13 11 | D | + | | | 65 66 | E | = | | - | 481 66 | (12) | , then add the two sides of equation (12) to both sides of equation (5), the equations are reduced to:
 | | | | | | | - | 6 11 | D | + | | | 5 11 | E | = | | - | 37 11 | | (4) |
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Multiply both sides of equation (5) by 30 Divide both sides of equation (5) by 11, get the equation:, then subtract both sides of equation (13) from both sides of equation (4), get the equation:
Multiply both sides of equation (5) by 18, get the equation:, then add the two sides of equation (14) to both sides of equation (3), get the equation:
Multiply both sides of equation (4) by 11 Divide both sides of equation (4) by 9, get the equation:, then add the two sides of equation (15) to both sides of equation (3), get the equation:
Multiply both sides of equation (4) by 11 Divide both sides of equation (4) by 6, get the equation:, then subtract both sides of equation (16) from both sides of equation (1), get the equation:
Multiply both sides of equation (3) by 3 Divide both sides of equation (3) by 11, get the equation:, then add the two sides of equation (17) to both sides of equation (1), get the equation:
Add both sides of equation (2) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |