detailed information: The input equation set is:
 | | | | | | | A | + | | 3 | B | + | | 3 | E | = | | - | 519 50 | | (3) |
| | | | 4 | A | + | | | 3923 1000 | E | = | | - | 1048 25 | | (5) |
| Question solving process:
交After the exchange of equation (1) and equation (3), the equation system becomes:
 | | | | | A | + | | 3 | B | + | | 3 | E | = | | - | 519 50 | | (1) |
| | | | | | 4 | A | + | | | 3923 1000 | E | = | | - | 1048 25 | | (5) |
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Multiply both sides of equation (1) by 4, the equation can be obtained: | | | 4 | A | + | | 12 | B | + | | 12 | E | = | | - | 1038 25 | (6) | , then subtract both sides of equation (6) from both sides of equation (5), the equations are reduced to:
 | | | | | A | + | | 3 | B | + | | 3 | E | = | | - | 519 50 | | (1) |
| | | | | -12 | B | | - | 8077 1000 | E | = | | - | 2 5 | | (5) |
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Multiply both sides of equation (2) by 3, the equation can be obtained: , then add the two sides of equation (7) to both sides of equation (3), the equations are reduced to:
 | | | | | A | + | | 3 | B | + | | 3 | E | = | | - | 519 50 | | (1) |
| | | | | -12 | B | | - | 8077 1000 | E | = | | - | 2 5 | | (5) |
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Add both sides of equation (2) to both sides of equation (4) ,the equations are reduced to:
 | | | | | A | + | | 3 | B | + | | 3 | E | = | | - | 519 50 | | (1) |
| | | | | -12 | B | | - | 8077 1000 | E | = | | - | 2 5 | | (5) |
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Multiply both sides of equation (2) by 12, the equation can be obtained: , then subtract both sides of equation (8) from both sides of equation (5), the equations are reduced to:
 | | | | | A | + | | 3 | B | + | | 3 | E | = | | - | 519 50 | | (1) |
| | | | | -12 | C | | -12 | D | | - | 8077 1000 | E | = | | - | 2 5 | | (5) |
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Divide the two sides of equation (3) by 3, the equation can be obtained: , then subtract both sides of equation (9) from both sides of equation (4), the equations are reduced to:
 | | | | | A | + | | 3 | B | + | | 3 | E | = | | - | 519 50 | | (1) |
| | | | | -12 | C | | -12 | D | | - | 8077 1000 | E | = | | - | 2 5 | | (5) |
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Multiply both sides of equation (3) by 4, the equation can be obtained: , then add the two sides of equation (10) to both sides of equation (5), the equations are reduced to:
 | | | | | A | + | | 3 | B | + | | 3 | E | = | | - | 519 50 | | (1) |
| | | | | | 8 | D | | - | 8077 1000 | E | = | | | 678 5 | | (5) |
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Multiply both sides of equation (4) by 12, the equation can be obtained: , then add the two sides of equation (11) to both sides of equation (5), the equations are reduced to:
 | | | | | A | + | | 3 | B | + | | 3 | E | = | | - | 519 50 | | (1) |
| | | | |
Multiply both sides of equation (5) by 1000 Divide both sides of equation (5) by 3923, get the equation:, then subtract both sides of equation (12) from both sides of equation (4), get the equation:
 | | | | | A | + | | 3 | B | + | | 3 | E | = | | - | 519 50 | | (1) |
| | | | - | 2 3 | D | = | | - | 132182 11769 | | (4) |
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Multiply both sides of equation (5) by 3000 Divide both sides of equation (5) by 3923, get the equation:| | | | 11769 3923 | E | = | | - | 1200 3923 | (13) | , then subtract both sides of equation (13) from both sides of equation (1), get the equation:
 | | | | | A | + | | 3 | B | = | | - | 1976037 196150 | | (1) |
| | | | - | 2 3 | D | = | | - | 132182 11769 | | (4) |
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Multiply both sides of equation (4) by 15 Divide both sides of equation (4) by 2, get the equation:, then add the two sides of equation (14) to both sides of equation (3), get the equation:
 | | | | | A | + | | 3 | B | = | | - | 1976037 196150 | | (1) |
| | | | - | 2 3 | D | = | | - | 132182 11769 | | (4) |
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Multiply both sides of equation (4) by 3 Divide both sides of equation (4) by 2, get the equation:, then add the two sides of equation (15) to both sides of equation (2), get the equation:
 | | | | | A | + | | 3 | B | = | | - | 1976037 196150 | | (1) |
| | -1 | B | + | | C | = | | - | 66091 3923 | | (2) |
| | | - | 2 3 | D | = | | - | 132182 11769 | | (4) |
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Divide both sides of equation (3) by 3, get the equation:, then subtract both sides of equation (16) from both sides of equation (2), get the equation:
 | | | | | A | + | | 3 | B | = | | - | 1976037 196150 | | (1) |
| | -1 | B | = | | - | 1569200 15389929 | | (2) |
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Multiply both sides of equation (2) by 3, get the equation:| | -3 | B | = | | - | 4707600 15389929 | (17) | , then add the two sides of equation (17) to both sides of equation (1), get the equation:
 | | | | | A | = | | - | 538840081 209145246 | | (1) |
| | -1 | B | = | | - | 1569200 15389929 | | (2) |
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The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
 | | | | | A | = | | - | 538840081 209145246 | | (1) |
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Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |