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On line solution of multivariate equations:
    First set the elements of the equation (i.e. the number of unknowns), then click the "Next" button to enter the coefficients of each element of the equation set, and click the "Next" button to obtain the solution of the equation set.
    Note that the coefficients of each element of the equation system can only be numbers, not algebraic expressions (including mathematical functions).
    Current location:Equations > Multivariate equations > Answer
detailed information:
The input equation set is:
 3B + 2D = 34    (1)
-1B + C + D = 0    (2)
 A + 3B + 3E = 
519
50
    (3)
 B + E = 0    (4)
 4A + 
3923
1000
E = 
1048
25
    (5)
Question solving process:

交After the exchange of equation (1) and equation (3), the equation system becomes:
 A + 3B + 3E = 
519
50
    (1)
-1B + C + D = 0    (2)
 3B + 2D = 34    (3)
 B + E = 0    (4)
 4A + 
3923
1000
E = 
1048
25
    (5)

Multiply both sides of equation (1) by 4, the equation can be obtained:
         4A + 12B + 12E = 
1038
25
    (6)
, then subtract both sides of equation (6) from both sides of equation (5), the equations are reduced to:
 A + 3B + 3E = 
519
50
    (1)
-1B + C + D = 0    (2)
 3B + 2D = 34    (3)
 B + E = 0    (4)
-12B 
8077
1000
E = 
2
5
    (5)

Multiply both sides of equation (2) by 3, the equation can be obtained:
        -3B + 3C + 3D = 0    (7)
, then add the two sides of equation (7) to both sides of equation (3), the equations are reduced to:
 A + 3B + 3E = 
519
50
    (1)
-1B + C + D = 0    (2)
 3C + 5D = 34    (3)
 B + E = 0    (4)
-12B 
8077
1000
E = 
2
5
    (5)

Add both sides of equation (2) to both sides of equation (4) ,the equations are reduced to:
 A + 3B + 3E = 
519
50
    (1)
-1B + C + D = 0    (2)
 3C + 5D = 34    (3)
 C + D + E = 0    (4)
-12B 
8077
1000
E = 
2
5
    (5)

Multiply both sides of equation (2) by 12, the equation can be obtained:
        -12B + 12C + 12D = 0    (8)
, then subtract both sides of equation (8) from both sides of equation (5), the equations are reduced to:
 A + 3B + 3E = 
519
50
    (1)
-1B + C + D = 0    (2)
 3C + 5D = 34    (3)
 C + D + E = 0    (4)
-12C -12D 
8077
1000
E = 
2
5
    (5)

Divide the two sides of equation (3) by 3, the equation can be obtained:
         C + 
5
3
D = 
34
3
    (9)
, then subtract both sides of equation (9) from both sides of equation (4), the equations are reduced to:
 A + 3B + 3E = 
519
50
    (1)
-1B + C + D = 0    (2)
 3C + 5D = 34    (3)
2
3
D + E = 
34
3
    (4)
-12C -12D 
8077
1000
E = 
2
5
    (5)

Multiply both sides of equation (3) by 4, the equation can be obtained:
         12C + 20D = 136    (10)
, then add the two sides of equation (10) to both sides of equation (5), the equations are reduced to:
 A + 3B + 3E = 
519
50
    (1)
-1B + C + D = 0    (2)
 3C + 5D = 34    (3)
2
3
D + E = 
34
3
    (4)
 8D 
8077
1000
E = 
678
5
    (5)

Multiply both sides of equation (4) by 12, the equation can be obtained:
        -8D + 12E = -136    (11)
, then add the two sides of equation (11) to both sides of equation (5), the equations are reduced to:
 A + 3B + 3E = 
519
50
    (1)
-1B + C + D = 0    (2)
 3C + 5D = 34    (3)
2
3
D + E = 
34
3
    (4)
 
3923
1000
E = 
2
5
    (5)

Multiply both sides of equation (5) by 1000
Divide both sides of equation (5) by 3923, get the equation:
         E = 
400
3923
    (12)
, then subtract both sides of equation (12) from both sides of equation (4), get the equation:
 A + 3B + 3E = 
519
50
    (1)
-1B + C + D = 0    (2)
 3C + 5D = 34    (3)
2
3
D = 
132182
11769
    (4)
 
3923
1000
E = 
2
5
    (5)

Multiply both sides of equation (5) by 3000
Divide both sides of equation (5) by 3923, get the equation:
         
11769
3923
E = 
1200
3923
    (13)
, then subtract both sides of equation (13) from both sides of equation (1), get the equation:
 A + 3B = 
1976037
196150
    (1)
-1B + C + D = 0    (2)
 3C + 5D = 34    (3)
2
3
D = 
132182
11769
    (4)
 
3923
1000
E = 
2
5
    (5)

Multiply both sides of equation (4) by 15
Divide both sides of equation (4) by 2, get the equation:
        -5D = 
330455
3923
    (14)
, then add the two sides of equation (14) to both sides of equation (3), get the equation:
 A + 3B = 
1976037
196150
    (1)
-1B + C + D = 0    (2)
 3C = 
197073
3923
    (3)
2
3
D = 
132182
11769
    (4)
 E = 
400
3923
    (5)

Multiply both sides of equation (4) by 3
Divide both sides of equation (4) by 2, get the equation:
        -1D = 
66091
3923
    (15)
, then add the two sides of equation (15) to both sides of equation (2), get the equation:
 A + 3B = 
1976037
196150
    (1)
-1B + C = 
66091
3923
    (2)
 3C = 
197073
3923
    (3)
2
3
D = 
132182
11769
    (4)
 E = 
400
3923
    (5)

Divide both sides of equation (3) by 3, get the equation:
         C = 
65691
3923
    (16)
, then subtract both sides of equation (16) from both sides of equation (2), get the equation:
 A + 3B = 
1976037
196150
    (1)
-1B = 
1569200
15389929
    (2)
 3C = 
197073
3923
    (3)
 D = 
66091
3923
    (4)
 E = 
400
3923
    (5)

Multiply both sides of equation (2) by 3, get the equation:
        -3B = 
4707600
15389929
    (17)
, then add the two sides of equation (17) to both sides of equation (1), get the equation:
 A = 
538840081
209145246
    (1)
-1B = 
1569200
15389929
    (2)
 C = 
65691
3923
    (3)
 D = 
66091
3923
    (4)
 E = 
400
3923
    (5)

The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
 A = 
538840081
209145246
    (1)
 B = 
1569200
15389929
    (2)
 C = 
65691
3923
    (3)
 D = 
66091
3923
    (4)
 E = 
400
3923
    (5)


Therefore, the solution of the equation set is:
A = 
538840081
209145246
B = 
1569200
15389929
C = 
65691
3923
D = 
66091
3923
E = 
400
3923


Convert the solution of the equation set to decimals:
A = -2.576392
B = 0.101963
C = -16.745093
D = 16.847056
E = -0.101963

解方程组的详细方法请参阅:《多元一次方程组的解法》