Mathematics
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current location:Mathematical operation > History of Inequality Computation
    (2x+1)(x-3)>3(x^2+2)
    -3x^2+4x+4>0
    x-5/x+1<2
    (x-3)/(2-x)<0
    (x-3)/(2-x)>=0
    0<(1+x)(1-2/3x)<1
    [(k+0.5)4k-50]/(k+0.5)>0
    -0.05<=(500x-0.02214-503.5088x+252.43405x^2)/(500x)<=0.05
    -0.05<=(500x-0.02214-503.5088+252.43405x^2)/(500x)<=0.05
    -0.05<=(500x-0.04441-502.1204x+251.5427x^2)/(500x)<=0.05
    -0.05<=(500x-0.01357-503.53533x+252.62243x^2)/(500x)<=0.05
    -0.05<=(500x-0.01357-503.53533x+252.62243x^2)/(500x)
    2t^2+11t+18<=0
    abs(3x+3)>=4-abs(x-2)
    (x+4)(x-5)>0
    1.05 ^ x > 1 + 0.1 * x
    x2一4x一12X>0
    (z+4)/(z+5)-(z-9)/(z-5)>0
    4x/(x-8)*(x+6)>0
    (x+2)/(x-8)<0

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