Mathematics
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current location:Mathematical operation > History of Inequality Computation
    3(x+2)>4x+2 x/2>=(x-1)/3
    1/2x+1<7-3/2x (3x-2)/3>=x/3+(x-4)/4
    (4+x)/2+1>=4(x+1)/3
    6x+15>2(4x+3) (2x-1)/3>=(1/2)x-2/3
    x-1>0 3(x+2)<5x
    6x-2>3x-4 (2x+1)/3-x/2<1
    4x-2>=3(x-1) (x-5)/2+1>x+3
    5x-2>3(x+1) (1/2)x-1<=7-(3/2)x
    10x>7x+6 x-1<(x+7)/3
    (3x-2)/3>=1 4x-5<3x+2
    5x-1<3(x+1) (2x-1)/3-(5x+1)/2<=1
    x-1>-2(x-1) (1-x)/2+10>=(x+2)/3
    3x+3>=2x+7 (2x+4)/3<3-x
    x/6+1>(x+2)/3
    x+(3x-1)<=2x-7
    xx-6x+8<0
    xx+6x-8>0
    (x-1)(5x-1)>0
    abs(x^2+2x-3)>1
    -x^2-2absx+3<0

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