Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality 1/（2^（k+1）） ≤0.05 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality：
        1 / ( 2 ^ ( k + 1 ) ) ≤0.05         (1)
        From the definition field of divisor
         2 ^ ( x + 1 ) ≠ 0        (2 )

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    From inequality(1)：
         k ≥ √19311611/√1750000
    From inequality(2)：
         k < -1083.465556 或  -1083.465556 < k < -1082.746667 或  -1082.746667 < k < -1082.027778 或  -1082.027778 < k < -1081.308889 或  -1081.308889 < k < -108059/100 或  -108059/100 < k < -242971/225 或  -242971/225 < k < -971237/900 或  -971237/900 < k < -32353/30 或  -32353/30 < k < -969943/900 或  -969943/900 < k < -1076.995556 或  k ＞ -1076.995556

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    From inequalities (1) and (2)
         k ≥ √19311611/√1750000    (3)

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    The final solution set is :
         k ≥ √19311611/√1750000

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