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current location:Mathematical operation > History of Inequality Computation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality (b^2-b-1+sqrt(b^2-2*b-3))/b小于1 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality:
         ( b ^ 2 - b - 1 + sqrt ( b ^ 2 - 2 * b - 3 ) ) / b <1         (1)
        From the definition field of √
         x ^ 2 - 2 * x - 3 ≥ 0        (2 )
        From the definition field of divisor
        x ≠ 0        (3 )

    From inequality(1):
         b ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!
    From inequality(2):
         b ≤ -1 或  b ≥ 3
    From inequality(3):
         b < 0 或  b > 0

    From inequalities (1) and (2)
         b ≤ -1 或  b ≥ 3    (4)
    From inequalities (3) and (4)
         b ≤ -1 或  b ≥ 3    (5)

    The final solution set is :

         b ≤ -1 或  b ≥ 3




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