Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality abs（b+1-sqrt（b^2-2b-3）-6*b*((b+1-sqrt（b^2-2b-3))/2b）^2+4*b*((b+1-sqrt（b^2-2b-3))/2b）^3）小于1 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality：
         abs ( b + 1 - sqrt ( b ^ 2 - 2 * b - 3 ) - 6 * b * ( ( b + 1 - sqrt ( b ^ 2 - 2 * b - 3 ) ) / 2 * b ) ^ 2 + 4 * b * ( ( b + 1 - sqrt ( b ^ 2 - 2 * b - 3 ) ) / 2 * b ) ^ 3 ) <1         (1)
        From the definition field of √
         x ^ 2 - 2 * x - 3 ≥ 0        (2 )
        From the definition field of √
         x ^ 2 - 2 * x - 3 ≥ 0        (3 )
        From the definition field of √
         x ^ 2 - 2 * x - 3 ≥ 0        (4 )

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    From inequality(1)：
         -1.473801 < b < -1.364263 或  b ＞ -1.258419
    From inequality(2)：
         b ≤ -1 或  b ≥ 3
    From inequality(3)：
         b ≤ -1 或  b ≥ 3
    From inequality(4)：
         b ≤ -1 或  b ≥ 3

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    From inequalities (1) and (2)
         -1.473801 < b < -1.364263 或  -1.258419 < b ≤ -1 或  b ≥ 3    (5)
    From inequalities (3) and (5)
         -1.473801 < b < -1.364263 或  -1.258419 < b ≤ -1 或  b ≥ 3    (6)
    From inequalities (4) and (6)
         -1.473801 < b < -1.364263 或  -1.258419 < b ≤ -1 或  b ≥ 3    (7)

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    The final solution set is :
         -1.473801 < b < -1.364263 或  -1.258419 < b ≤ -1 或  b ≥ 3

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