Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality (12.5x*x/(4-x*x)-3x*x+2)/(25x/(4-x*x)-5*x) >(2.5x*x*x/(4-x*x)+x*x+1.5x+1+(2*(25x*x)/(4*(4-x*x))-2.5x*x+x*x+1)/(1+x*x))/((-5x*(1-5/(4-x*x)))/(1+x*x)) .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality：
         ( 12.5 * x * x / ( 4 - x * x ) - 3 * x * x + 2 ) / ( 25 * x / ( 4 - x * x ) - 5 * x ) > ( 2.5 * x * x * x / ( 4 - x * x ) + x * x + 1.5 * x + 1 + ( 2 * ( 25 * x * x ) / ( 4 * ( 4 - x * x ) ) - 2.5 * x * x + x * x + 1 ) / ( 1 + x * x ) ) / ( ( -5 * x * ( 1 - 5 / ( 4 - x * x ) ) ) / ( 1 + x * x ) )         (1)
        From the definition field of divisor
         4 - x * x ≠ 0        (2 )
        From the definition field of divisor
         4 - x * x ≠ 0        (3 )
        From the definition field of divisor
         25 * x / ( 4 - x * x ) - 5 * x ≠ 0        (4 )
        From the definition field of divisor
         4 - x * x ≠ 0        (5 )
        From the definition field of divisor
         4 * ( 4 - x * x ) ≠ 0        (6 )
        From the definition field of divisor
         1 + x * x ≠ 0        (7 )
        From the definition field of divisor
         4 - x * x ≠ 0        (8 )
        From the definition field of divisor
         1 + x * x ≠ 0        (9 )
        From the definition field of divisor
         ( -5 * x * ( 1 - 5 / ( 4 - x * x ) ) ) / ( 1 + x * x ) ≠ 0        (10 )

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    From inequality(1)：
         -0.912584 < x < -0.654213 或  x ＞ 2.802696
    From inequality(2)：
         x < -2 或  -2 < x < 2 或  x ＞ 2
    From inequality(3)：
         x < -2 或  -2 < x < 2 或  x ＞ 2
    From inequality(4)：
         x < -2 或  -2 < x < 0 或  0 < x < 2 或  x ＞ 2
    From inequality(5)：
         x < -2 或  -2 < x < 2 或  x ＞ 2
    From inequality(6)：
         x < -2 或  -2 < x < 2 或  x ＞ 2
    From inequality(7)：
         x ∈ R （R为全体实数），即在实数范围内，不等式恒成立！
    From inequality(8)：
         x < -2 或  -2 < x < 2 或  x ＞ 2
    From inequality(9)：
         x ∈ R （R为全体实数），即在实数范围内，不等式恒成立！
    From inequality(10)：
         x < -2 或  -2 < x < 0 或  0 < x < 2 或  x ＞ 2

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    From inequalities (1) and (2)
         -0.912584 < x < -0.654213 或  x ＞ 2.802696    (11)
    From inequalities (3) and (11)
         -0.912584 < x < -0.654213 或  x ＞ 2.802696    (12)
    From inequalities (4) and (12)
         -0.912584 < x < -0.654213 或  x ＞ 2.802696    (13)
    From inequalities (5) and (13)
         -0.912584 < x < -0.654213 或  x ＞ 2.802696    (14)
    From inequalities (6) and (14)
         -0.912584 < x < -0.654213 或  x ＞ 2.802696    (15)
    From inequalities (7) and (15)
         -0.912584 < x < -0.654213 或  x ＞ 2.802696    (16)
    From inequalities (8) and (16)
         -0.912584 < x < -0.654213 或  x ＞ 2.802696    (17)
    From inequalities (9) and (17)
         -0.912584 < x < -0.654213 或  x ＞ 2.802696    (18)
    From inequalities (10) and (18)
         -0.912584 < x < -0.654213 或  x ＞ 2.802696    (19)

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    The final solution set is :
         -0.912584 < x < -0.654213 或  x ＞ 2.802696

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