Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality log((x+1),(x^2+x-6)^2) >= 4 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality：
         log( ( x + 1 ) , ( x ^ 2 + x - 6 ) ^ 2 ) >= 4         (1)
        From the definition field of log
         ( x + 1 ) > 0        (2 )
         ( x ^ 2 + x - 6 ) ^ 2 > 0 also ≠ 1        (3 )

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    From inequality(1)：
         0 ≤ x ≤ 1
    From inequality(2)：
         x ＞ -1
    From inequality(3)：
         x < -3.192582 或  -3.192582 < x < -3 或  -3 < x < -2.791288 或  -2.791288 < x < 1.791288 或  1.791288 < x < 2 或  2 < x < 2.192582 或  x ＞ 2.192582

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    From inequalities (1) and (2)
         0 ≤ x ≤ 1    (4)
    From inequalities (3) and (4)
         0 ≤ x ≤ 1    (5)

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    The final solution set is :
         0 ≤ x ≤ 1

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