Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality （absx-3）(x^2+absx-2) ≤0 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality：
         ( abs x - 3 ) * ( x ^ 2 + abs x - 2 ) ≤0         (1)

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    From inequality(1)：
         -3 ≤ x ≤ -1 或  1 ≤ x ≤ 3

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    The final solution set is :
         -3 ≤ x ≤ -1 或  1 ≤ x ≤ 3

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