Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality x+sqrt(x^2+16) <8 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality：
         x + sqrt ( x ^ 2 + 16 ) <8         (1)
        From the definition field of √
         x ^ 2 + 16 ≥ 0        (2 )

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    From inequality(1)：
         x < 3
    From inequality(2)：
         x ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!

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    From inequalities (1) and (2)
         x < 3    (3)

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    The final solution set is :
         x < 3

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