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    Work: Find the solution of equation （x+2）/5-（x-1）/4 = 0 .
    Question type: Equation
    Solution:Original question:

(

x

+

2

)

÷

5

−

(

x

−

1

)

÷

4

=

0

    Remove the bracket on the left of the equation:

Left side of the equation =

x

×

1 5

+

2

×

1 5

−

(

x

−

1

)

×

1 4

=

x

×

1 5

+

2 5

−

(

x

−

1

)

×

1 4

=

1 5

x

+

2 5

−

x

×

1 4

+

1

×

1 4

=

1 5

x

+

2 5

−

x

×

1 4

+

1 4

=

-

1 20

x

+

13 20

    The equation is transformed into :

-

1 20

x

+

13 20

=

0

    Transposition :

-

1 20

x

=

0

−

13 20

    Combine the items on the right of the equation:

-

1 20

x

=

-

13 20

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :

13 20

=

1 20

x

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :

1 20

x

=

13 20

    The coefficient of the unknown number is reduced to 1 :

x

=

13 20

÷

1 20

=

13 20

×

20

=

13

×

1

    We obtained :

x

=

13

    This is the solution of the equation.

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