Mathematics
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current location:Mathematical operation > History of Inequality Computation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality e((-a-2+sqrt(a^2+8))/2)*(1-a*((-a-2+sqrt(a^2+8))/2)-((-a-2+sqrt(a^2+8))/2)^2) <= 1 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality:
         e ( ( -a - 2 + sqrt ( a ^ 2 + 8 ) ) / 2 ) * ( 1 - a * ( ( -a - 2 + sqrt ( a ^ 2 + 8 ) ) / 2 ) - ( ( -a - 2 + sqrt ( a ^ 2 + 8 ) ) / 2 ) ^ 2 ) <= 1         (1)
        From the definition field of √
         x ^ 2 + 8 ≥ 0        (2 )
        From the definition field of √
         x ^ 2 + 8 ≥ 0        (3 )
        From the definition field of √
         x ^ 2 + 8 ≥ 0        (4 )

    From inequality(1):
        x ∈ Φ (Φ is empty)that is, the inequality will never be estatlished within the real number range!
    From inequality(2):
         a ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!
    From inequality(3):
         a ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!
    From inequality(4):
         a ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!

    From inequalities (1) and (2)
        x ∈ Φ (Φ is empty)that is, the inequality will never be estatlished within the real number range!    (5)
    From inequalities (3) and (5)
        x ∈ Φ (Φ is empty)that is, the inequality will never be estatlished within the real number range!    (6)
    From inequalities (4) and (6)
        x ∈ Φ (Φ is empty)that is, the inequality will never be estatlished within the real number range!    (7)

    The final solution set is :

        x ∈ Φ (Φ is empty)that is, the inequality will never be estatlished within the real number range!




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