Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality abs(3k-2+3) >= sqrt(k^2+1) .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality：
         abs ( 3 * k - 2 + 3 ) >= sqrt ( k ^ 2 + 1 )         (1)
        From the definition field of √
         x ^ 2 + 1 ≥ 0        (2 )

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    From inequality(1)：
         k ≤ -3/4 或  k ≥ 0
    From inequality(2)：
         k ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!

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    From inequalities (1) and (2)
         k ≤ -3/4 或  k ≥ 0    (3)

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    The final solution set is :
         k ≤ -3/4 或  k ≥ 0

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