Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality (10^(-6))+(10^(-21))*(f^2) >= (5*10^(-6)*f+500)/((2500*f+f+10^(8))*(-0.15)) .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality：
         ( 10 ^ ( -6 ) ) + ( 10 ^ ( -21 ) ) * ( f ^ 2 ) >= ( 5 * 10 ^ ( -6 ) * f + 500 ) / ( ( 2500 * f + f + 10 ^ ( 8 ) ) * ( -0.15 ) )         (1)
        From the definition field of divisor
         ( 2500 * x + x + 10 ^ ( 8 ) ) * ( -0.15 ) ≠ 0        (2 )

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    From inequality(1)：
        The solution set is empty, that is, within the range of real numbers, the inequality will never be established!
    From inequality(2)：
         f ∈ R （R为全体实数），即在实数范围内，不等式恒成立！

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    The final solution set is :
        The solution set is empty,that is, the inequality will never be estatlished within the real number range.

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