Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality 8/(abs(x)+2)-2 <= 0 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality：
        8 / ( abs ( x ) + 2 ) - 2 <= 0         (1)
        From the definition field of divisor
         abs ( x ) + 2 ≠ 0        (2 )

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    From inequality(1)：
         x ≤ -2 或  x ≥ 2
    From inequality(2)：
         x ∈ R （R为全体实数），即在实数范围内，不等式恒成立！

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    From inequalities (1) and (2)
         x ≤ -2 或  x ≥ 2    (3)

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    The final solution set is :
         x ≤ -2 或  x ≥ 2

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