Mathematics
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current location:Mathematical operation > History of Inequality Computation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality {{k+[k^2+(sin30)^2-2k*(sin30)^2]^(1/2)}^2+k^2-2k{k+[k^2+(sin30)^2-k(sin30)^2]^(1/2)}}^(1/2) <= sin30+1-k .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality:
         ( ( k + ( k ^ 2 + ( sin 30 ) ^ 2 - 2 * k * ( sin 30 ) ^ 2 ) ^ ( 1 / 2 ) ) ^ 2 + k ^ 2 - 2 * k * ( k + ( k ^ 2 + ( sin 30 ) ^ 2 - k * ( sin 30 ) ^ 2 ) ^ ( 1 / 2 ) ) ) ^ ( 1 / 2 ) <= sin 30 + 1 - k         (1)

    From inequality(1):
         k ≤ -0.964238

    The final solution set is :

         k ≤ -0.964238

    *Note: Radian.



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