current location:Mathematical operation >
History of Inequality Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 inequalities
[ 1/1Inequality]
Assignment:Find the solution set of inequality {{k+[k^2+(sin30)^2-2k*(sin30)^2]^(1/2)}^2+k^2-2k{k+[k^2+(sin30)^2-k(sin30)^2]^(1/2)}}^(1/2) <= sin30+1-k .
Question type: Inequality
Solution:
The inequality can be reduced to 1 inequality:
( ( k + ( k ^ 2 + ( sin 30 ) ^ 2 - 2 * k * ( sin 30 ) ^ 2 ) ^ ( 1 / 2 ) ) ^ 2 + k ^ 2 - 2 * k * ( k + ( k ^ 2 + ( sin 30 ) ^ 2 - k * ( sin 30 ) ^ 2 ) ^ ( 1 / 2 ) ) ) ^ ( 1 / 2 ) <= sin 30 + 1 - k (1)
From inequality(1):
k ≤ -0.964238
The final solution set is :
k ≤ -0.964238 *Note: Radian.Your problem has not been solved here? Please take a look at the hot problems !