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current location:Mathematical operation > History of Inequality Computation > Answer
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           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation N*129*0.2+400 = 3(N*129*0.2+400) .
    Question type: Equation
    Solution:Original question:
      N × 129 ×
1
5
+ 400 = 3( N × 129 ×
1
5
+ 400)
     Left side of the equation = N ×
129
5
+ 400
    The equation is transformed into :
     
129
5
N + 400 = 3( N × 129 ×
1
5
+ 400)
    Remove the bracket on the right of the equation:
     Right side of the equation = 3 N × 129 ×
1
5
+ 3 × 400
                                               =
387
5
N + 1200
    The equation is transformed into :
     
129
5
N + 400 =
387
5
N + 1200

    Transposition :
     
129
5
N
387
5
N = 1200400

    Combine the items on the left of the equation:
      -
258
5
N = 1200400

    Combine the items on the right of the equation:
      -
258
5
N = 800

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
      - 800 =
258
5
N

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
     
258
5
N = - 800

    The coefficient of the unknown number is reduced to 1 :
      N = - 800 ÷
258
5
        = - 800 ×
5
258
        = - 400 ×
5
129

    We obtained :
      N = -
2000
129
    This is the solution of the equation.

    Convert the result to decimal form :
      N = - 15.503876




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