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[ 1/1 Equation]
Work: Find the solution of equation （b-4）（b-4）-4（-b+14） = 0 .
Question type: Equation
Solution:Original question:| | ( | b | − | 4 | ) | ( | b | − | 4 | ) | − | 4 | ( | - | b | + | 14 | ) | = | 0 |
Remove the bracket on the left of the equation:
| Left side of the equation = | b | ( | b | − | 4 | ) | − | 4 | ( | b | − | 4 | ) | − | 4 | ( | - | b | + | 14 | ) |
| = | b | b | − | b | × | 4 | − | 4 | ( | b | − | 4 | ) | − | 4 | ( | - | b | + | 14 | ) |
| = | b | b | − | 4 | b | − | 4 | b | + | 4 | × | 4 | − | 4 | ( | - | b | + | 14 | ) |
| = | b | b | − | 4 | b | − | 4 | b | + | 16 | − | 4 | ( | - | b | + | 14 | ) |
| = | b | b | − | 8 | b | + | 16 | − | 4 | ( | - | b | + | 14 | ) |
| = | b | b | − | 8 | b | + | 16 | + | 4 | b | − | 4 | × | 14 |
| = | b | b | − | 8 | b | + | 16 | + | 4 | b | − | 56 |
The equation is transformed into :
The solution of the equation:
b1≈-4.633250 , keep 6 decimal places
b2≈8.633250 , keep 6 decimal places
There are 2 solution(s).
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