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           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation （19-m）（300+30m） = 6300 .
    Question type: Equation
    Solution:Original question:

(

19

−

m

)

(

300

+

30

m

)

=

6300

    Remove the bracket on the left of the equation:

Left side of the equation =

19

(

300

+

30

m

)

−

m

(

300

+

30

m

)

=

19

×

300

+

19

×

30

m

−

m

(

300

+

30

m

)

=

5700

+

570

m

−

m

(

300

+

30

m

)

=

5700

+

570

m

−

m

×

300

−

m

×

30

m

=

5700

+

270

m

−

m

×

30

m

    The equation is transformed into :

5700

+

270

m

−

m

×

30

m

=

6300

    After the equation is converted into a general formula, it is converted into:
    ( m - 4 )( m - 5 )=0
    From
        m - 4 = 0
        m - 5 = 0
    it is concluded that:：
        m₁=4
        m₂=5    
    There are 2 solution(s).

解一元二次方程的详细方法请参阅：《一元二次方程的解法》

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