Mathematics
语言：中文
Language:English

current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation （1+m/2%）×1000×（1+m%）×500 = 660000 .
    Question type: Equation
    Solution:Original question:
     (1 + m ÷
2
100
) × 1000(1 + m ) × 500 = 660000
     Left side of the equation = (1 + m ÷
2
100
) × 500000(1 + m )
    The equation is transformed into :
     (1 + m ÷
2
100
) × 500000(1 + m ) = 660000
    Remove the bracket on the left of the equation:
     Left side of the equation = 1 × 500000(1 + m ) + m ÷
2
100
 × 500000(1 + m )
                                             = 500000(1 + m ) + m × 25000000(1 + m )
                                             = 500000 × 1 + 500000 m + m × 25000000(1 + m )
                                             = 500000 + 500000 m + m × 25000000(1 + m )
                                             = 500000 + 500000 m + m × 25000000 × 1 + m × 25000000 m
                                             = 500000 + 500000 m + m × 25000000 + m × 25000000 m
                                             = 500000 + 25500000 m + m × 25000000 m
    The equation is transformed into :
     500000 + 25500000 m + m × 25000000 m = 660000

    
        m=20    
    There are 1 solution(s).

解一元一次方程的详细方法请参阅：《一元一次方程的解法》



Your problem has not been solved here? Please take a look at the  hot problems ！


Return