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current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 6 questions will be solved this time.Among them
           ☆6 equations

[ 1/6 Equation]
    Work: Find the solution of equation 80-2x = 28 .
    Question type: Equation
    Solution:Original question:
     80 − 2 x = 28

    Transposition :
      - 2 x = 28 − 80

    Combine the items on the right of the equation:
      - 2 x = - 52

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
     52 = 2 x

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
     2 x = 52

    The coefficient of the unknown number is reduced to 1 :
      x = 52 ÷ 2
        = 52 ×
1
2
        = 26 × 1

    We obtained :
      x = 26
    This is the solution of the equation.

[ 2/6 Equation]
    Work: Find the solution of equation 2x-2 = 7 .
    Question type: Equation
    Solution:Original question:
     2 x − 2 = 7

    Transposition :
     2 x = 7 + 2

    Combine the items on the right of the equation:
     2 x = 9

    The coefficient of the unknown number is reduced to 1 :
      x = 9 ÷ 2
        = 9 ×
1
2

    We obtained :
      x =
9
2
    This is the solution of the equation.

    Convert the result to decimal form :
      x = 4.5

[ 3/6 Equation]
    Work: Find the solution of equation 5x+2 = 5 .
    Question type: Equation
    Solution:Original question:
     5 x + 2 = 5

    Transposition :
     5 x = 5 − 2

    Combine the items on the right of the equation:
     5 x = 3

    The coefficient of the unknown number is reduced to 1 :
      x = 3 ÷ 5
        = 3 ×
1
5

    We obtained :
      x =
3
5
    This is the solution of the equation.

    Convert the result to decimal form :
      x = 0.6

[ 4/6 Equation]
    Work: Find the solution of equation 6x+4x = 320 .
    Question type: Equation
    Solution:Original question:
     6 x + 4 x = 320
     Left side of the equation = 10 x
    The equation is transformed into :
     10 x = 320

    The coefficient of the unknown number is reduced to 1 :
      x = 320 ÷ 10
        = 320 ×
1
10
        = 32 × 1

    We obtained :
      x = 32
    This is the solution of the equation.

[ 5/6 Equation]
    Work: Find the solution of equation 9x÷3 = 1.2 .
    Question type: Equation
    Solution:Original question:
     9 x ÷ 3 =
6
5
     Left side of the equation = 3 x
    The equation is transformed into :
     3 x =
6
5

    The coefficient of the unknown number is reduced to 1 :
      x =
6
5
 ÷ 3
        =
6
5
 ×
1
3
        =
2
5
 × 1

    We obtained :
      x =
2
5
    This is the solution of the equation.

    Convert the result to decimal form :
      x = 0.4

[ 6/6 Equation]
    Work: Find the solution of equation 72-7x = 16 .
    Question type: Equation
    Solution:Original question:
     72 − 7 x = 16

    Transposition :
      - 7 x = 16 − 72

    Combine the items on the right of the equation:
      - 7 x = - 56

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
     56 = 7 x

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
     7 x = 56

    The coefficient of the unknown number is reduced to 1 :
      x = 56 ÷ 7
        = 56 ×
1
7
        = 8 × 1

    We obtained :
      x = 8
    This is the solution of the equation.




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