There are 1 questions in this calculation: for each question, the 2 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ second\ derivative\ of\ function\ sin(60 - x)cos(60 - x)\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = sin(-x + 60)cos(-x + 60)\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( sin(-x + 60)cos(-x + 60)\right)}{dx}\\=&cos(-x + 60)(-1 + 0)cos(-x + 60) + sin(-x + 60)*-sin(-x + 60)(-1 + 0)\\=&-cos^{2}(-x + 60) + sin^{2}(-x + 60)\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( -cos^{2}(-x + 60) + sin^{2}(-x + 60)\right)}{dx}\\=&--2cos(-x + 60)sin(-x + 60)(-1 + 0) + 2sin(-x + 60)cos(-x + 60)(-1 + 0)\\=&-4sin(-x + 60)cos(-x + 60)\\ \end{split}\end{equation} \]

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