Mathematics
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current location:Derivative function > Derivative function calculation history > Answer
    There are 1 questions in this calculation: for each question, the 1 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ first\ derivative\ of\ function\ xy(x - 1)(y - 1)(x - y)(x + y - 1)\ with\ respect\ to\ x:\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = y^{2}x^{4} - 2y^{2}x^{3} - y^{4}x^{2} + 2y^{3}x^{2} - yx^{4} + 2yx^{3} + y^{4}x - 2y^{3}x - yx^{2} + y^{2}x\\&\color{blue}{The\ first\ derivative\ function:}\\&\frac{d\left( y^{2}x^{4} - 2y^{2}x^{3} - y^{4}x^{2} + 2y^{3}x^{2} - yx^{4} + 2yx^{3} + y^{4}x - 2y^{3}x - yx^{2} + y^{2}x\right)}{dx}\\=&y^{2}*4x^{3} - 2y^{2}*3x^{2} - y^{4}*2x + 2y^{3}*2x - y*4x^{3} + 2y*3x^{2} + y^{4} - 2y^{3} - y*2x + y^{2}\\=&4y^{2}x^{3} - 6y^{2}x^{2} - 2y^{4}x + 4y^{3}x - 4yx^{3} + 6yx^{2} - 2yx - 2y^{3} + y^{4} + y^{2}\\ \end{split}\end{equation} \]





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