There are 1 questions in this calculation: for each question, the 1 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ first\ derivative\ of\ function\ 16{x}^{3} + 3cos(x) + 4tan(x)cos(x)\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = 16x^{3} + 4cos(x)tan(x) + 3cos(x)\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( 16x^{3} + 4cos(x)tan(x) + 3cos(x)\right)}{dx}\\=&16*3x^{2} + 4*-sin(x)tan(x) + 4cos(x)sec^{2}(x)(1) + 3*-sin(x)\\=&48x^{2} - 4sin(x)tan(x) + 4cos(x)sec^{2}(x) - 3sin(x)\\ \end{split}\end{equation} \]

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