There are 1 questions in this calculation: for each question, the 1 derivative of x is calculated.
Note that variables are case sensitive.\[ \begin{equation}\begin{split}[1/1]Find\ the\ first\ derivative\ of\ function\ \frac{2cos(x)sin(2)x}{3}\ with\ respect\ to\ x:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = \frac{2}{3}xsin(2)cos(x)\\&\color{blue}{The\ first\ derivative\ function:}\\&\frac{d\left( \frac{2}{3}xsin(2)cos(x)\right)}{dx}\\=&\frac{2}{3}sin(2)cos(x) + \frac{2}{3}xcos(2)*0cos(x) + \frac{2}{3}xsin(2)*-sin(x)\\=&\frac{2sin(2)cos(x)}{3} - \frac{2xsin(x)sin(2)}{3}\\ \end{split}\end{equation} \]Your problem has not been solved here? Please take a look at the hot problems !